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2 years ago

10

Hurry please! I will give the right answer brainliest! A developer has 7 1/2 acres of land to build houses on. If each house is

to be built on 1/4 -acre plot, how many houses can he build?

2 answers:

aev [14]2 years ago

8 0

Answer:

$\boxed {\boxed {\sf 30 \ houses}}$

Step-by-step explanation:

Each house uses 1/4 acres and there is a total of 7 1/2 acres. Therefore, we can divide the total land by the land used for one house.

$7 \frac{1}{2} \div \frac{1}{4}$

First, convert the mixed number to an improper fraction.

An easy way to do this is by multiplying the denominator or bottom number of the fraction (2) by the whole number (7). Then, add the numerator (1).

2*7=14
14+1 =15

This becomes the numerator of the improper fraction and the denominator stays the same. The fraction is 15/2

$\frac{15}{2} \div \frac{1}{4}$

Now, divide the fractions. Multiply by the reciprocal of the second fraction and follow Keep Change Flip.

Keep the first fraction. Change the division sign to a multiplication symbol.

$\frac{15}{2} \times \frac{1}{4}$

Flip the second fraction. Switch the numerator and denominator.

$\frac{15}{2} \times \frac{4}{1}$

Multiply across.

$\frac{(15*4)}{(2*1)}$

$\frac{60}{2} =30$

<u>30 houses can be built.</u>

Harrizon [31]2 years ago

3 0

Answer:

30 if I divided correctly ☺

Step-by-step explanation:

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The following data set represents the age of

Julli [10]

$\huge\text{Hey there!}$

$\huge\textsf{Breaking the meaning down in simpler terms}$
$\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}$

$\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}$

$\huge\textsf{Formulas for each term}$

$\huge\text{Median:}\\\large\textsf{To find the median you have to put each of your numbers in your data}\\\large\textsf{set from LEAST (smallest) to GREATEST (biggest). }$

$\huge\text{Mean:}\\\mathsf{\dfrac{sum\ of\ all\ terms}{number\ of\ terms}= mean}$

$\huge\textbf{SOLVING FOR THE QUESTION}$

$\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}$

$\huge\textsf{Mean:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textsf{Your equation: }\mathsf{\dfrac{27 + 52 + 64 + 41 + 33 + 38 + 42 + 60 +72 + 68}{10}}\\\\\mathsf{\dfrac{79 + 64 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{143 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{184 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{217 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{255 + 42 + 60 + 72 + 68}{10}}$

$\mathsf{\dfrac{297 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{357 + 72 + 68}{10}}\\\\\mathsf{\dfrac{429 + 68}{10}}\\\\\mathsf{\dfrac{497}{10}}\\\\\mathsf{\approx 49.70}\\\\\large\text{From the looks of it \boxed{\rm{\dfrac{497}{10}}}\ or \boxed{\text{49.70}} could possibly be your mean.}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

<h3>
~ $\frak{Amphitrite1040:)}$ </h3>

8 0

2 years ago

Sholpan [36]

Answer:

Larry must mow approximately 25 lawns before he starts making a profit

Step-by-step explanation:

8 0

2 years ago

If carl was born in 1931 how old is he now

vfiekz [6]

86 years old because you subtract 2017-1931

7 0

3 years ago

Read 2 more answers

As a membership fee a health club charges a one time amount of $40 and charges $25 for each month. The total fee after m months

ICE Princess25 [194]

First you need to set up an equation y = mx + b. m would be the monthly charge and b would be the one time fee. x represents the number of months.
To solve for the number of months with a total price of 240 we substitute 240 in for y and solve for x.
240 = 25x + 40
subtract 40 from each side
200= 25x
divide by 25
8 = x
8 months

10 + 7r = 45
7r = 35
r = 5
5 miles

3 0

2 years ago

An animal feed to be mixed from soybean meal and oats must contain at least 168 lb of protein, 27 lb of fat, and 14 lb of minera

atroni [7]

Answer:

The animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

$Cost = 51.275$

Step-by-step explanation:

The given parameters can be summarized as:

$\begin{array}{cccc}{} & {x} & {y} & {Total} & {Protein} & {70} & {21} & {168} &{Fats}& {9} & {7} & {27} & {Minerals} & {7} & {1} & {14}& {Cost} & {21} & {7} & {} \ \end{array}$

Where: x = Soybeans and y = Oats.

So, the system of equations are:

$70x + 21y = 168$

$9x +7y = 27$

$7x + y = 14$

$Cost = 21x + 7y$

The best way to solve this, is using graph

Plot the following equations on a graph, and get the points of intersection:

$70x + 21y = 168$

$9x +7y = 27$

$7x + y = 14$

From the attached graph, we have:

$(x_1,y_1) = (1.636,2.545)$

$(x_2,y_2) = (1.775,1.575)$

$(x_3,y_3) = (2.023,1.256)$

Substitute each of the values of x's and y's in the cost function to get the minimum cost:

$Cost = 21x + 7y$

$(x_1,y_1) = (1.636,2.545)$

$Cost = 21 * 1.636 + 7 * 2.545$

$Cost = 52.171$

$(x_2,y_2) = (1.775,1.575)$

$Cost = 21 * 1.775 + 7 * 1.575$

$Cost = 48.3$

$(x_3,y_3) = (2.023,1.256)$

$Cost = 21 * 2.023 + 7 * 1.256$

$Cost = 51.275$

The values of x and y that gives the minimum cost is:

$(x_2,y_2) = (1.775,1.575)$

and the minimum cost is:

$Cost = 48.3$

Hence, the animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

5 0

3 years ago