Answer:
1/12
Step-by-step explanation:
P( coin = heads) = number of heads / total = 1/2
P( cube = 5) = number of 5's / total =1/6
P( heads, 5) =1/2 * 1/6 = 1/12
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Assuming the order does not matter, you want the number of combinations of 9 things taken 5 at a time. The combinations can be shown as C(9,5), 9C5.
C(9, 5) =
9/5(9-5) =
9*8*7*6*5 / 5*4
The 5 terms cancel.
9*8*7*6 / 4*3*2 =
9*7*2 =
126
The above change is because 4*2 cancels the 8 in the numerator and 6/3 = 2
Therefore, the solution is 126.
your answer would be 30
<em>HOPE THAT HELPS!!!</em>
Answer:
6 13/14
Step-by-step explanation:
Convert 2/7 to 4/14 by multiplying both 2/7 by 2/2, to have a common denominator, then add your mixed numbers.
2/7 x 2/2 = 4/14
4/14 + 9/14 = 13/14
4 + 2 = 6
6 13/14
