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2 years ago

5

An isosceles triangle has an angle that measures 110°. Which other angles could be in that isosceles triangle? Choose all that a

pply.
20°, 35°, 20°, 80°

1 answer:

Stolb23 [73]2 years ago

8 0

The answer is ,
Only 35 degrees...
As the other option won’t make the sum of the interior angles 180..

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Please Help!!! Evaluate the following <br><br> 2/((3-(3-1))*3-1)

antiseptic1488 [7]

2/ 3 - (3 - 1) * 3 - 1 = -4
Simplify
= 2/-4
which is
= -2/4
Then simplify again
= -1/2

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3 years ago

The market equilibrium point for a product is reached when 12000 units are produced and sold at $27 per unit. The manufacturer w

mamaluj [8]

If the equilibrium is such that only 12000 units are sold for $27, then the total earnings from the given scenario is $324,000. The supply equation would then be,
supply: 324000 = 6p ; p = 324000/6 = 54000
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3 years ago

Which of the following is the point and slope of the equation y - 8 = 4(x + 3)? a. (8, -3), 4 b. (3, -8), 4 c. (-8, 3), 4 d. (-3

pychu [463]

Answer:

d

Step-by-step explanation:

This is point-slope form, and these coordinates make both sides equal to 0.

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10 months ago

I have to math questions i need help with. If one of the factors x^2+27x+152 is x+8, what is the other factor? and Factor the fo

alexgriva [62]

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Step-by-step explanation:

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3 years ago

1) Lithium isotope rations are important to medicine, the 6Li/7Li ratio in a standard reference material was measured several ti

uysha [10]

Answer:

1) $0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

b) $ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=0.0826052$ represent the sample mean

$\mu$ population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size

Part 1

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=5-1=4$

The Confidence level is 0.95 or 95%, and the significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ , the critical value would be using the t distribution with 4 degrees of freedom: $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

Part 2

The original margin of error is given by:

$ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

3 0

3 years ago