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aev [14]
3 years ago
14

Express your answer in the smaller unit: 231 m 31 cm - 14 m 48 cm

Mathematics
1 answer:
pashok25 [27]3 years ago
6 0
23131-1448 =21683(cm)

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PLEASE HELP! NEED TO SUBMIT SOON! NOT SURE IF I GOT THE RIGHT ANSWERS! THANK YOU IN ADVANCE!!!
Eddi Din [679]
Nice

4s=amount of grams of protine in straberry for s ounces
3b=amount of grams of protine in banana for b ouces

total ounces is 6
s+b=6

total grams is 22
4s+3b=22

s+b=6
4s+3b=22
those are the 2 equations

a.
s+b=6
4s+3b=22


b. elmination, we can elminate alll the b's and have 1s left

c.
multiply first equaiton by -3 and add to second

4s+3b=22
<u>-3s-3b=-18 +</u>
1s+0b=4
s=4
sub
s+b=6
4+b=6
minus 4
b=2

4 oz straberry
2 oz banana
8 0
3 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
I'll mark as Brainliest, Please answer ASAP, Ihave MCAS tomorrow. How could this be true?? Please Explain.​
iragen [17]

Answer:

D

Step-by-step explanation:

Put  m+2  in place of 'x'

   (m+2)^2 + 1               <======expand

   m^2 + 4m + 4       + 1   =

   m^2   + 4m + 5

8 0
2 years ago
Given: Parallelogram KLMN
kozerog [31]

Answer:

Since, KLMN is a parallelogram, then by the property of parallelogram that opposite angles of a parallelogram is equal, therefore ∠N=∠L and ∠M=∠K.

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
It took Kathy 8 minutes to run a mile. It took her 48 minutes to run 5 miles. How many times as long did it take Kathy to run th
kotykmax [81]
Divide 48 by 8. Therefore 6 times.
4 0
3 years ago
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