Answer:
y = x-2
Step-by-step explanation:
y = mx + b as an equation
m = slope
slope = (change in y) / (change in x) = (y₂-y₁)/(x₂-x₁) = (y₁-y₂)/(x₁-x₂) = (2-(-2))/(4-0) = 4/4 = 1
y = 1*x + b
plug a value in, e.g. (0, -2)
-2 = 1 * 0 + b
-2 = b
our equation is thus
y = x - 2
Answer:
B. y= -x^2+50x-300
Step-by-step explanation:
A. y^2=4x^2-100
B. y= -x^2+50x-300
C. x=-y^2-400
D. x^2=-6y^2+200
we are to find profits (y) when the company sells x items
Option A can be used to calculate the profit (y) squared
Option B can be used to calculate profits (y)
Option C can be used to calculate items sold(x)
Option D can be used to calculate items sold squared(x^2)
We are asked to find the weekly profit (y) function which eliminate options A, C and D leaving us with option B
Therefore, the weekly profits (y) function in thousands of dollars when the company sells x items is
B. y= -x^2+50x-300
You have in the first equation "+y" and in the second "-y"
So, you add the 2 equations, so we can remove this 2 letters since they're opposite numbers.
So, we get:
-4x + y -5x - y = 21 + 6
-4x -5x = 21 + 6
Then, you add
-4x -5x = 21 + 6
-9x = 27
Then, you move the -9 to the other part, next to the 27. And since it was a multiplication, it becomes a division.
x =


Then, you choose an equation of the system, and you replace x by it's value so you can find y. I'll take the first equation.
-4x + y = 6
-4*-3 + y = 6
12 + y = 6
Then, you move 12 to the other part next to the 6. And since it was a positive number, it becomes a negative number.
So
y = 6 - 12
y = -6
So, the solution of the proposed system <span>is (x;y) = (6;-6)
x = 6
y = -6
Hope this Helps :)
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Answer: The upper quartile is 12.
In a box and whiskers plot, the point on the right edge of the box is called the upper quartile. In this case, that value is 12. It represents the median of the upper half of the set of data.
Answer:
3. 3 : 5; 3: 5
Step-by-step explanation:
First, let's find the leght of the sides of each octagon.

The area of an octagon is defined by

Replacing the area

Therefore, the side of the first octagon is 1.6 inches long.
Its perimeter is: 


Therefore, the side of the second octagon is 3.8 inches long.
Its perimeter is
.
Now, let's divide to find each ratio:
(the ratio between sides).
(the ratio between perimeters).
Therefore, the closest ratio is 3. 3 : 5; 3: 5