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3 years ago

What is the area of an equilateral triangle with sides of length 20?

Mathematics

1 answer:

Anarel [89]3 years ago

6 0

Answer:

173.2

Step-by-step explanation:

area of equilateral triangle = √3 / 4 l^2

so area =173.2

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Use the grouping method to factor x3 + x2 + 2x + 2.

chubhunter [2.5K]

$x^3+x^2+2x+2$

$x^2(x+1)+2(x+1)=(x^2+2)(x+1)$

4 0

3 years ago

Read 2 more answers

What is measure of side A?

Ira Lisetskai [31]

Answer:

The correct answer option is c. a = 11.94.

Step-by-step explanation:

We are given a right angles triangle with an angle ABC equal to 58 degrees and side length AC known to be equal to 19.1.

We are supposed to find the length of side a.

Side AC, opposite to angle ABC, will be the perpendicular and BC will be the base so we will use the formula of tan to find b.

$tan 58 = \frac{19.1}{a}$

$a = \frac{19.1}{tan 58}$

$a=11.94$

8 0

4 years ago

By using Euler's formula, find the number of edges of a polyhedron with 16 faces and 20 vertices

Lina20 [59]

Answer:

34 edges

Step-by-step explanation:

Euler's formula for polyhedron states

F + V - E = 2

where F is number of faces, V, number of vertices, E number of edges

Here F = 16, V = 20, thus

16 + 20 - E = 2, that is

36 - E = 2 ( subtract 36 from both sides )

- E = - 34 ( multiply both sides by - 1 )

E = 34

8 0

3 years ago

A music Web site announced that over

Stells [14]

Step-by-step explanation:

Average=total numbers of songs /registered users

Average= 4*10^9/5*10^7

Average=40*10^8/5*10^7

Average=8*10^(8-7)

Average=8*10^(1)

Average=80 songs downloaded per user

8 0

3 years ago

For each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts. A large shipmen

Stella [2.4K]

Answer:

(a) The p-value of the test statistic should be 0.33.

(b) No, there is not sufficient evidence to reject the entire shipment.

Step-by-step explanation:

We are given that for each shipment of parts a manufacturer wants to accept only those shipments with at most 10% defective parts.

A quality control manager randomly selects 50 of the parts from the shipment and finds that 6 parts are defective.

Let p = proportion of defective parts among the current shipment.

So, Null Hypothesis, $H_0$ : p $\leq$ 10% {means that the defective parts in the shipment is at most 10%}

Alternate Hypothesis, $H_A$ : p > 10% {means that the defective parts in the shipment is greater 10%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of parts that are defective among the current shipment = $\frac{6}{50}$ = 12%

n = sample of parts from the shipment = 50

So, test statistics = $\frac{0.12-0.10}{\sqrt{\frac{0.12(1-0.12)}{50} } }$

= 0.44

The value of z test statistics is 0.44.

(a) Now, P-value of the test statistics is given by the following formula;

P-value = P(Z > 0.44) = 1 - P(Z $\leq$ 0.44)

= 1 - 0.67003 = 0.3299 ≈ 0.33

(b) Since, the P-value of test statistics is more than the level of significance as 0.33 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the defective parts in the shipment is at most 10%.

4 0

3 years ago