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3 years ago

Measures of Center and Variability

Mathematics

2 answers:

pickupchik [31]3 years ago

3 0

1. The mean of all the numbers is 41.
5. Median : 52

defon3 years ago

3 0

The mean is 41
And
The median is 52

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Which of the following is a solution of y - x < -3?

azamat

Answer:

Step-by-step explanation:

$Subtract- y- from- both -sides.\\-x (less than)-3-y\\2 Multiply both sides by -1.\\x (greater than ) 3+y$

5 0

3 years ago

Read 2 more answers

Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 505050 meters.

Dennis_Churaev [7]

Answer= 70.7 meters.

Step-by-step explanation:

We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.

Since we know that diagonal of a square is product of side length of square and . So we will find diagonal of our given square plaza by multiplying 50 by .

Therefore, diagonal distance across the plaza is 70.7 meters.

3 0

3 years ago

Anyone know how to do #21?

Andreas93 [3]

Would it be y2 ? idk im not sure but i tried

6 0

3 years ago

Expand each expression

matrenka [14]

Answer:

Option B - $\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Step-by-step explanation:

Given : Expression $\ln(\frac{4y^5}{x^2})$

To find : Expand each expression ?

Solution :

Using logarithmic properties,

$\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B$

and $\ln (AB)=\ln A+\ln B$

Here, A=4y^5 and B=x^2

$\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}$

$\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2$

$\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2$

Using logarithmic property, $\logx^a=a\log x$

$\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Therefore, option B is correct.

3 0

3 years ago

Read 2 more answers

What's the surface area ?

Morgarella [4.7K]

Answer:

ans = 112

Step-by-step explanation:

Hope it will help

please mark as brainlists

3 0

2 years ago