Answer:
the common differnence is positive 3
Step-by-step explanation:
its going back by 3 since its going back to 0 its positive
Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable: 
Therefore, 
Variance of binomial random variable: 
Therefore, 
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Answer:
20 5/8 yd^2
Step-by-step explanation:
width = 3 3/4 yd
length = 5 1/2 yd
First change both measurements to fractions.
3 3/4 = 3 + 3/4 = 12/4 + 3/4 = 15/4
5 1/2 = 5 + 1/2 = 10/2 + 1/2 = 11/2
area = length * width
area = 15/4 yd * 11/2 yd
area = (15 * 11)/(4 * 2) yd^2
area = 165/8 yd^2
165/8 = 20 remainder 5
area = 20 5/8 yd^2
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