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fenix001 [56]
4 years ago
8

An oak tree grows at a rate of 3 3/5 inches per month. How much will the tree grow in 6 1/2 months? :P

Mathematics
1 answer:
MakcuM [25]4 years ago
8 0

Answer:

A) 23 2/5 inches                  PLEASE MARK BRAINLIEST

Step-by-step explanation:

1/5 = 0.2

1/2 = 0.5

So

3/5 = 0.6

3 + 0.6 = 3.6

6 + 0.5 = 6.5

3.6 x 6.5 = 23.4

Which is 23 2/5

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Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
Which angles are congruent to each other
katrin2010 [14]

Answer:

Step-by-step explanation:

um

4 0
3 years ago
Israel planted 4 tomato seeds in his garden. Then he planted flower seeds in each of his three neighbor's gardens. Which express
Mice21 [21]

Answer:

4 + 3n

Step-by-step explanation:

Number of seed planed in his garden = 4

Let the Number of seed planted in each neighbor's garden = n

Number of neighbors he has = 3

The total number of seeds planted can be represented by the equation :

Number of seeds planted in his garden + (number of neighbors * number of seeds planted in each neighbors garden)

4 + 3n

7 0
3 years ago
Martin thinks of two numbers. He says, "The Highest Common Factor (HCF) of my two numbers is 6 The Lowest Common Multiple (LCM)
sergiy2304 [10]

Answer:

30 and 42

Hope this helps

3 0
3 years ago
Evaluate the expression 8p6
Margaret [11]

Answer:

Evaluate 8P6 P 6 8 using the formula nPr=n!(n−r)! P r n = n ! ( n - r ) ! . 8!(8−6)! 8 ! ( 8 - 6 ) ! Subtract 6 6 from 8 8 . 8!(2)! 8 ! ( 2 ) ! Simplify 8!(2)! 8 !

Step-by-step explanation:

evaluate" usually means to put a value in for the variable, but you don't give us a value for p. also, it is unclear if you ...

8 0
3 years ago
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