Answer:
(a) 21
(b)2520
Step-by-step explanation:
(a)
Using combination formula, nCr where n is the total sample and r is the limitation hence 7 combination 5.
[tex}7C5=\frac {7*6*5*4*3}{5*4*3*2*1}=\frac {2520}{120}=21[/tex]
(b)
If the scholarships are not equal
The number of ways to select the 5 students from 7 we use permutation formula hence
7P5 = 7*6*5*4*3 = 2520
0 ≤ q ≤ 5/3 (this is the answer if you’re looking for the inequality of q)
Answer:
i)
Variables: length of bolt, number of flaws of bolt
ii)
Length of bolt: Quantitative continuous
number of flaws of bolt: Quantitative discrete
iii)
Observational unit: Bolts
iv)
sample size=75
Step-by-step explanation:
i)
The variables in the conducted study are "length of bolt" and "number of flaws on each bolt" because quality engineer is interested in evaluating the length of bolt and the number of flaws each bolt is having. Thus, the length and number of flaws for each bolt varies and we can say that "length of bolt" and "number of flaws on each bolt" are two variables in the conducted study.
ii)
The length of bolt can be presented numerically and further that the length of a bolt is measurable and thus, the length of bolt is a quantitative continuous variable.
The number of flaws of each bolt can be presented numerically and further that the number of flaws of each bolt can be counted and thus, the number of flaws of each bolt is a quantitative discrete variable.
iii)
The conducted study indicates that observational units are "bolts" because for each bolt its length and flaws are determined.
iv)
The sample size is 75 because a quality engineer selected 75 bolts and then measured its length and flaws.
Answer:
3
Step-by-step explanation:
