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forsale [732]
3 years ago
14

Which of these is least likely to describe

Mathematics
1 answer:
dexar [7]3 years ago
8 0

Answer:

integer

Step-by-step explanation:

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Identify the three similar right triangles in the given diagram.
irga5000 [103]

Answer:

B. ΔABD, ΔADC, ΔDBC

Step-by-step explanation

Step -1 In ΔABD and ΔADC (from figure).

∠DAB=∠CAD (common in both triangles) ,

∠DBA=∠CDA =90 degree, and

∠BDA=∠DCA (rest angle of the two triangles).

therefore ΔABD similar to ΔADC (by AAA similarity theorem).

Step -2 In ΔDBC and ΔADC (from figure).

∠DCB=∠ACD (common in both triangles) ,

∠DBC=∠ADC =90 degree, and

∠CDB=∠CAD (rest angle of the two triangles).

therefore ΔDBC similar to ΔADC (by AAA similarity theorem).

Step -3 In ΔABD and ΔDBC (from figure).

∠BDA=∠BCD (because , ∠ACD=ADB from stap-1 and ∠ACD=∠BCD from figure) ,

∠DBA=∠CBD =90 degree, and

∠BAC=∠BDC (rest angle of the two triangles).

therefore ΔABD similar to ΔDBC (by AAA similarity theorem).

In the above step- ΔABD similar to ΔADC, ΔDBC similar to ΔADC and ΔABD similar to ΔDBC.

Hence ΔABD, ΔADC, ΔDBC similar to each other in the given figure.

4 0
3 years ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista
Yuki888 [10]
d=v \cdot t
d - distance
v - speed
t - time

Car A:
v_1 \\
t_1=2 \\
d_1=v \cdot 2=2 v

Car B:
15 mph faster than car A
v_2=v_1+15 \\ t_2=1.5 \\ d_2= (v_1+15) \cdot 1.5=1.5v_1 + 22.5

Both cars traveled equal distances:
d_1=d_2 \\
2v_1 = 1.5v_1+22.5 \\
2v_1-1.5v_1=22.5 \\
0.5v_1=22.5 \\
v_1=45 \\ v_2=45 + 15 =60

Car B traveled at the speed of 60 mph.
6 0
3 years ago
UITE
max2010maxim [7]
A logical conclusion would say “Kelly is 15 minutes late to school.”
4 0
2 years ago
the formula for the area of a square s to the 2nd power, where s is the side length of the square. What is the area of a square
Helen [10]

The answer to this is 36.

5 0
2 years ago
Let p(x) = x^2 + 8x + 12 and q(x) = x^3 + 5x^2 - 6x. Define r(x) = p(x) \cdot q(x).
Anna [14]

The roots of the entire <em>polynomic</em> expression, that is, the product of p(x) = x^2 + 8x + 12 and q(x) = x^3 + 5x^2 - 6x, are <em>x₁ =</em> 0, <em>x₂ =</em> -2, <em>x₃ =</em> -3 and <em>x₄ =</em> -6.

<h3>How to solve a product of two polynomials </h3>

A value of <em>x</em> is said to be a root of the polynomial if and only if <em>r(x) =</em> 0. Let be <em>r(x) = p(x) · q(x)</em>, then we need to find the roots both for <em>p(x)</em> and <em>q(x)</em> by factoring each polynomial, the factoring is based on algebraic properties:

<em>r(x) =</em> (x + 6) · (x + 2) · x · (x² + 5 · x - 6)

<em>r(x) =</em> (x + 6) · (x + 2) · x · (x + 3) · (x + 2)

r(x) = x · (x + 2)² · (x + 3) · (x + 6)

By direct inspection, we conclude that the roots of the entire <em>polynomic</em> expression are <em>x₁ =</em> 0, <em>x₂ =</em> -2, <em>x₃ =</em> -3 and <em>x₄ =</em> -6. \blacksquare

To learn more on polynomials, we kindly invite to check this verified question: brainly.com/question/11536910

5 0
2 years ago
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