The sum of first 46 positive and odd numbers is 2116
<em><u>Solution:</u></em>
Given that we have to find the sum of first 46 positive and odd numbers
<em><u>The sum of first "n" natural odd numbers which are positive is given as:</u></em>
Here, n = 46
Therefore,
sum of first 46 positive and odd numbers = 
sum of first 46 positive and odd numbers = 
Thus the sum of first 46 positive and odd numbers is 2116
Answer:
an = 8 - 2*(n - 1)
Step-by-step explanation:
a1 ; .... ; an-1 ; an
r = an - an-1
r = (an-1 - 2) - an-1
r = an-1 - 2 - an-1
r = -2
So:
an = a1 + r*(n - 1)
an = 8 + (-2)*(n - 1)
an = 8 - 2*(n - 1)
Answer:
(n/4) - 5 = 2(n-14)
Step-by-step explanation:
let the number be n
"25% of n" : (25/100)n = n/4
"Five less than 25% of n" : (n/4) - 5
"difference between the number and 14" : n - 14
" twice the difference between the number and 14" : 2(n-14)
Assembling all the parts:
(n/4) - 5 = 2(n-14)
Answer:
7. 1/10 or 10%
9.5/10
11.5/10
13.9/10
Step-by-step explanation:
Answer: B repeating domain is 1
Step-by-step explanation: Repeat domain is not a function. Hope this help:)
