
Substract '-3.4x' at LHS nad the RHS of the above expression.

Add '4' on both LHS and RHs of the above expression.
Answer:
x=6 . m<PQS=82 m<SQR=61 :)
Step-by-step explanation:
(13x+4) + (10x-1) = 141
combine like terms
23x+3=141
subtract 3 from both sides
23x=138
divide both sides by 23
x=6
substitute x into both original equations
m<PQS=13(6)+4
m<PQS=78+4
m<PQS= 82
m<SQR=10(6)+1
m<SQR=60+1
M<SQR=61
Answer:
2. 10
3. D. 1 for all n
Step-by-step explanation:
2. The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^b = 1/a^-b
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
The value of n is 10.
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3. Using the above rules of exponents, the expression simplifies to ...
6^(-n+n) = 6^0 = 1
The value is 1 for any n.
This is True
answered false got it wrong