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madreJ [45]
2 years ago
9

________ can be written only once. The data cannot be erased or written over once it is saved.​

Computers and Technology
1 answer:
notka56 [123]2 years ago
6 0

Answer:

WORM (Write Once, Read Many)

Explanation:

The full meaning which means Write Once, Read Many implies that data can only be entered (or better put, written) once. Once the data has been written, the data can not be updated or deleted. However, the data being stored on WORM can be read as many times, as possible.

Hence, WORM answers the question.

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The "A" in the CIA triad stands for "authenticity". True False
mihalych1998 [28]

Answer: False, the "A" in the CIA triad stands for <em>availability</em><em>.</em>

The CIA triad also know as the Confidentiality, integrity and availability triad, is known as a model which is designed in order to implement and enforce policies in regards to information security. This model is also referred as the availability, integrity and confidentiality model i.e AIC triad. This is done in order to avoid confusion with Central Intelligence Agency i.e. CIA.

8 0
3 years ago
Two devices used by the supermarket point-of-sale (POS) terminal are a bar code reader and a keyboard. Name two other input/outp
Svetllana [295]

Answer:

1. Receipt printer

Use of receipt printer:

i. They are used to print customer transaction receipts for proof.

2. Touch screen monitor

Use of touch screen monitor:

i. Allow record of when, where, price, and other important information about the sale conducted.

Explanation:

A Point of sale (POS) terminal takes record of transactions at the point where a product is purchased or a service is rendered. A barcode reader is a price scanner that is an input device used in a point-of-sale (POS) terminal. The keyboard is also an input device. The receipt printer is an output device since it converts information into a readable format. While only a touch screen monitor among the other devices mentioned above is an input and output device, because of its touch panel and its ability to display information.

             

6 0
2 years ago
Serious Question: Do English-speaking programmers find it easier to learn a new programming language?
Scrat [10]

Answer:

a programming language is relatively easy to learn for a programmer, although all the frameworks of modern languages, never mind their underlying architectures and all the tools that are available mean that it will take at least half a year to get into the same sort of level of proficiency as somebody that

Explanation:

7 0
3 years ago
Any radio hardware containing a transmitter and a receiver that is located in a fixed location is called a _______
arsen [322]

Answer:

base station

Explanation:

According to my research on information technology, I can say that based on the information provided within the question this type of radio hardware is referred to as a base station. These are tied to a fixed location and used to communicate as part of either: a push-to-talk two-way radio system, or a wireless telephone system such as cellular CDMA or GSM.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

4 0
4 years ago
write a program that first asks the user to enter three real numbers using GUI input. Print the sum if all three numbers are pos
den301095 [7]

Answer:

Here is the complete program:

import javax.swing.JOptionPane;  //to use GUI in JAVA application

import java.util.Scanner;  //to take input from user at console

public class Main {

public static void main(String[] args) {  //start of main function body

 String num1, num2,num3;  //declare three variables to store strings of numbers for input dialog

 double number1, number2, number3, sum,product; //declare three double type variables to hold the real numbers  

 num1 = JOptionPane.showInputDialog("num1");  //shows a dialog box prompting user to enter value of first number i.e. num1

 number1 = Double.parseDouble(num1);  //scans and reads the value of first input number i.e. number1    

 num2 = JOptionPane.showInputDialog("num2");  //shows a dialog box prompting user to enter value of second number i.e. num2

 number2 = Double.parseDouble(num2);   //reads number2  

               num3 = JOptionPane.showInputDialog("num3");  //shows a dialog box prompting user to enter value of third number i.e. num3

 number3 = Double.parseDouble(num3);   //reads number3  

   if(number1>0&& number2>0 && number3>0){  //checks if all three numbers are positive

   sum = number1 + number2+ number3;  //displays the sum by adding all three positive numbers

   JOptionPane.showMessageDialog(null, "the sum is : " + sum , "Results", JOptionPane.PLAIN_MESSAGE );      }   // displays the result of sum in a message dialog box

 

    if(number1<0 && number2>0 && number3>0)      {  //checks if number2 and number3 are positive

   product = number2*number3;  //computes product

   JOptionPane.showMessageDialog(null, "the product is : " + product , "Results", JOptionPane.PLAIN_MESSAGE );      }  //displays the result

   else if (number2<0&&number1>0&&number3>0){  //checks if number1 and number3 are positive

    product = number1*number3;  //computes product

JOptionPane.showMessageDialog(null, "the product is : " + product , "Results", JOptionPane.PLAIN_MESSAGE );      }  //displays the result

   else if (number3<0 && number1>0 && number2>0)     {  //checks if number1 and number2 are positive

     product = number1*number2;  //computes product of 2 positive numbers

     JOptionPane.showMessageDialog(null, "the product is : " + product , "Results", JOptionPane.PLAIN_MESSAGE );      }  //displays the result

   else     {  /.if all the numbers are positive.

/*However this part is optional. You can just use else part for above else if statement and exclude this else part. In this way the product of all three positive numbers is not computed and product is only computed when only two numbers of the three are positive */

     product = number1*number2*number3;  //computes product of all three positive numbers

     JOptionPane.showMessageDialog(null, "the product is : " + product , "Results", JOptionPane.PLAIN_MESSAGE );      }   //displays the result

Scanner scan = new Scanner(System.in);  //creates a Scanner class object

double value1 , value2, quotient;  //declares variables to hold the values of two real numbers and the result of division of the two real numbers is stored in quotient variable

System.out.println("Enter the first real number: ");  //prompts user to enter the value of first real number from the console

value1 = scan.nextDouble();  //reads the first number from user

System.out.println("Enter the second real number : ");  //prompts user to enter the value of second real number from the console

value2 = scan.nextDouble();  //reads the second number from user

if(value1<0&&value2<0)  {  //checks if both the numbers are negative

quotient = value1/value2;  //compute the quotient

JOptionPane.showMessageDialog(null, "the quotient is : " + quotient , "Results", JOptionPane.PLAIN_MESSAGE );    }  //displays result

 else  //if both numbers are not negative

JOptionPane.showMessageDialog(null, "Both numbers are not negative" );   //displays this message in a dialog box

  }  }

Explanation:

In the above given code if you want to display the outputs in console then alter the following statements as follows:

   if(number1>0&& number2>0 && number3>0){

   sum = number1 + number2+ number3;

  System.out.println("the sum is :  " + sum); }      

 

    if(number1<0 && number2>0 && number3>0)      {

    product = number2*number3;

      System.out.println("the product is :  " + product); }          

   else if (number2<0&&number1>0&&number3>0){

          product = number1*number3;

System.out.println("the product is :  " + product);      }

   else if (number3<0 && number1>0 && number2>0)     {

     product = number1*number2;

     System.out.println("the product is :  " + product);     }

   else     {

     product = number1*number2*number3;

      System.out.println("the product is :  " + product);      }

Scanner scan = new Scanner(System.in);

double value1 , value2, quotient;

System.out.println("Enter the first real number: ");

value1 = scan.nextDouble();

System.out.println("Enter the second real number : ");

value2 = scan.nextDouble();

if(value1<0&&value2<0)  {

quotient = value1/value2;

 System.out.println("the quotient is :  " + quotient);   }

 else  

System.out.println("Both numbers are not negative");

Notice that all the JOptionPane.showMessageDialog statement are changed with System.out.println which prints the results on the console.

4 0
3 years ago
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