Answer:
Knowledge of hazardous workspace conditions
If you have machines doing jobs, fewer staff is needed, therefore the costs are LESS.
Hope I helped!
Wheels should be pointing towards the curb. this is in case your vehicle rolls, if it does, the wheel will hit the curb and stop the car, it will also prevent the car from going into the road and incoming traffic. vice versa when parking uphill, point wheels away from curb, that is also to prevent the car from rolling to incoming traffic.
What language are you programming in?
<span>If you are programming in C or C++, you could do something like this: </span>
<span>#include <iostream> </span>
<span>using namespace std; </span>
<span>int main(void) </span>
<span>{ </span>
<span>//declarations </span>
<span>double item1 = 0; </span>
<span>double item2 = 0; </span>
<span>double item3 = 0; </span>
<span>double item4 = 0; </span>
<span>double item5 = 0; </span>
<span>double subtotal = 0; </span>
<span>double total = 0; </span>
<span>double tax = 0; </span>
<span>//Enter Items </span>
<span>cout << "Please enter the price of item 1"; </span>
<span>cin >> item1; </span>
<span>cout << "Please enter the price of item 2"; </span>
<span>cin >> item2; </span>
<span>cout << "Please enter the price of item 3"; </span>
<span>cin >> item3; </span>
<span>cout << "Please enter the price of item 4"; </span>
<span>cin >> item4; </span>
<span>cout << "Please enter the price of item 5"; </span>
<span>cin >> item5; </span>
<span>//Compute subtotal </span>
<span>subtotal = (item1 + item2 + item3 + item4 + item5 + item6); </span>
<span>//Compute amount of tax </span>
<span>tax = subtotal * (.06); </span>
<span>//Compute total </span>
<span>total = subtotal + tax; </span>
<span>//Display subtotal, total, and amount of tax </span>
<span>cout < " The subtotal of the sale is: " << subtotal << endl; </span>
<span>cout < " The amount of sales tax is: " << tax << endl; </span>
<span>cout < " The total of the sale is: " << total << endl; </span>
<span>return 0; </span>
<span>}//end of function main </span>
<span>I know this is a very very basic C++ program but I hope it helps and good luck on your project!</span>
Answer:
The correct answer for the given question is " The Code fragment A runs fastly than the code fragment of B".
Explanation:
In this question there are some information is missing i. e options. The question does not give any options. The options for the given question is given below
(A.) The Code fragment A runs fastly than the code fragment of B.
(B.) The Code fragment B runs fastly than code fragment of A.
(C) The Code fragment A runs as fastly as code fragment of B.
So we conclude the answer i.e option(A) because As given in the question list1 is a MyArrayList and list2 is a MyLinkedList. , in list1 we fetching the data easily and fastly means that it remove the data easily as compare to list2 As MyArrayList is storing the list only and also we can fetch the data easily manner.
The list2 is an object of MyLinkedList means that it manipulating the data fastly as compared to MyArrayList but if we compared the fetching of data then MyArrayList is a better option so the code fragment runs fastly then code fragmented B.