def is_list_even(my_list):
for i in my_list:
if(i%2 != 0):
return False
return True
def is_list_odd(my_list):
for i in my_list:
if(i%2 == 0):
return False
return True
def main():
n = int(input())
lst = []
for i in range(n):
lst.append(int(input()))
if(is_list_even(lst)):
print('all even')
elif(is_list_odd(lst)):
print('all odd')
else:
print('not even or odd')
if __name__ == '__main__':
main()
Answer:
By being a part of a block to a block chain and each block in the block chain is precisely connected to the block that was before it.
Explanation:
I Hope This Helps You
Answer:
printArray(inventory, n);
Explanation:
The question doesn't specify in which language this has to be done, here's a generic call then... so if it's aimed at a specific language, some minor adjustments might be needed to respect the proper syntax/structure of that specific language.
Given:
printArray: function name, using 2 parameters.
inventory: array of ints
n : integer, number of items in array inventory
The call to the function would be:
printArray(inventory, n);
Answer:
well it game
Explanation:
its gamw because you have to be smart with word njbhjvkgv
