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otez555 [7]
3 years ago
13

Solve 0= 2t^3-21t^2+ 40t

Mathematics
1 answer:
sukhopar [10]3 years ago
4 0
0=2t^3-21^2+40t
switch sides
2t^3-21t^2+40t=0
solve factoring 
t(t-8)(2t-5)=0
using the zero factor principle
t=0

solve
t-8=0:t=8
solve
2t-5=0:t= \frac{5}{2}
t=0,t=8,t= \frac{5}{2}
Hope this helps

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