Question

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Answer 1

Required Answer :-

Given system of linear equations are ,

• x + y = 2
• -3x + y = 2

And we need to find the Solution of the linear equation . So let's Firstly number the equations .

$\large{\red{\frak{ Given}}}\begin{cases} \sf x + y = 2\qquad ..........(i) \\\\\sf -3x + y = 2 \qquad ..........(ii) \\\end{cases}$

→ Multiplying equⁿ (i) by 3 ,

=> 3 ( x + y ) = 2*3

=> 3x + 3y = 6

→ Adding the two equations ,

=> 3x + 3y -3y + y = 6 + 2

=> 4y = 8

=> y = 8/4

=> y = 2

→ Put y = 2 in (i) ,

=> x + y = 2

=> x + 2 = 2

=> x = 2- 2

=> x = 0

★ Hence the required solution is ( 0 , 2 ) .