9514 1404 393
Answer:
6x^2 +64x yd²
Step-by-step explanation:
The total horizontal width is ...
w = (x -2) +(3x) = 4x -2 . . . yards
So, the width of the downward-extending leg at right is ...
(4x -2) -(2x -2) = 2x
The total vertical height is ...
10 yds + 40 yds = 50 yds
So, the height of the downward-extending leg at right is ...
50 -3x . . . yards
__
Then the empty rectangle at upper right has an area of ...
A = LW = (3x yds)(10 yds) = 30x yd²
and the empty rectangle at lower left has an area of ...
A = LW = (2x -2 yds)(50 -3x yds) = -6x^2 +106x -100 yd²
__
The total area is the product of overall width and overall height, less the areas of the two empty rectangles:
A = (4x -2 yds)(50 yds) -30x yd² -(-6x^2 +106x -100) yd²
A = 6x^2 +64x yd² . . . . . area of the proposed parking lot
