Here is all I got for you. From the starting expression to the simplest one.
t^2 + 4tv + 4^2 =
t^2 + 4tv + 16 =
t(t + 4v) + 16
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.
Tell me if you need any clarification
PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds
Tell me if you need any clarification
Answer:
Step-by-step explanation:
(1, 5.5) ; (2, 9)
Slope = 
= 7/2
m = 7/2 ; (2 , 9)
y - y1 =m(x -x1)
Multiply the equation by 2
Answer:
0
Step-by-step explanation:
4x+ 2( 3 – 3x) = 6
4x+6-6x=6
6-2x=6
6-6=2x
0/2=x
x=0
