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Scorpion4ik [409]
3 years ago
6

At Noon the temperature was 93.7 degrees

Mathematics
2 answers:
bazaltina [42]3 years ago
5 0
All u have to do is subtract both of the temps and then u will have to answer
Westkost [7]3 years ago
4 0
The temperature dropped 11.8 degrees

You just subtract 93.7 from 81.9 and that will get you your answer

93.7-81.9= 11.8
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\underline \mathcal \pink{ GIVEN}

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  • Height = 4 6/7 km

\underline \mathcal \purple{ TO  \: FIND}

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\underline \mathcal \blue{CALCULATION}

\qquad \tt \leadsto \: area =  \frac{1}{2}  \times base \times height

\qquad \bf \nrightarrow \: area =  \frac{1}{ \cancel2}  \times  \cancel2 \frac{9}{10}  \times 4 \frac{6}{7}

\qquad \bf \nrightarrow \: area =   \frac{9}{ \cancel{10}}  \times  \cancel4 \frac{6}{7}

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2 years ago
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Lina20 [59]

Answer:

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Step-by-step explanation:

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Subtract 117 from both sides:

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Hope this helps!

6 0
3 years ago
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8 0
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Vinil7 [7]

Answer:

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