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marysya [2.9K]
3 years ago
13

The graph of which function has an axis of symmetry at x = 3? f(x) = x2 3x 1 or f(x) = x2 – 3x – 3 or f(x) = x2 6x 3 or f(x) = x

2 – 6x – 1
Mathematics
2 answers:
Wittaler [7]3 years ago
6 0
For
ax^2+bx+c
the axis of symmetry is -b/2a


first one
-3/2=3, nope

2nd one
3/2=3? nope

3rd one
-6/2=3? nope

fourth
6/2=3? yes
answer is last one or
f(x)=x^2-6x-1
Bumek [7]3 years ago
5 0

Answer:

Option 4th is correct

f(x) = x^2-6x-1

Step-by-step explanation:

A quadratic equation is in the form of: y=ax^2+bx+c.....[1]; then the axis of symmetry is given by:

x = \frac{-b}{2a}

As per the statement:

To find :

The graph of which function has an axis of symmetry at x = 3

From the given options:

Option 4th is the graph of a function which has axis of symmetry at x = 3

Consider a function:

f(x) =x^2-6x-1

On comparing with [1] we have;

a = 1  and b = -6

then;

x = \frac{-(-6)}{2 \cdot 1}

⇒x = \frac{6}{2} =3

Therefore, The graph of which function has an axis of symmetry at x = 3 is, f(x) = x^2-6x-1

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A little help here lol
inysia [295]

Answer:D

Step-by-step explanation:

It’s asking for it’s opposite

4 0
3 years ago
Read 2 more answers
261,256,251 find the 50th term
marshall27 [118]

Answer:

a_{50}=16

Step-by-step explanation:

Given that,

An airthmetic sequence,

261,256,251

We need to find the 50th term.

We have,

first term, a = 261

common difference = 256-261 = -5

The nth term of the AP is given by :

a_n=a+(n-1)d\\\\a_{50}=a+49d\\\\a_{50}=261+49(-5)\\\\a_{50}=16

So, the 50th term of the sequence is 16.

7 0
3 years ago
I need help with this problem PLEASE HELP
xxTIMURxx [149]

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

<h3>How to Determine the Range and the Domain of a Function?</h3>

In any given graph that represents a function, the possible set of domain values are plotted on the x-axis (horizontal axis), while the possible set of corresponding range values are plotted on the y-axis (vertical axis).

Thus, the set of x-values (input values) on a graph is the domain of the function while the set of y-values (output values) is the range of the function.

In the given graph, the set of x-values are: -5, -3, -1, and 1.

The set of y-values are: -5, -3, -1, and 1.

Therefore:

The domain of the function is: {-5, -3, -1, 1}

The range of the function is: {-5, -3, -1, 1}

Learn more about the domain and range of a function on:

brainly.com/question/10197594

#SPJ1

7 0
1 year ago
What are the zeros of y=x^2 +2x -8
Igoryamba
Y = x² + 2x - 8

which two numbers add up to 2 and multiply to -8?

-2 and 4

so rewrite the expression using the above;

(x - 2)(x + 4)
x = 2, -4

so the zeros are 2 and -4.

hope this helps, God bless!
6 0
3 years ago
Read 2 more answers
*PLEASE HELLLPPPP ME ASAP* I HAVE BEEN STUCK ON THIS FOR DAYS
Kruka [31]
It would be +1 -1 because it goes down 1 every time
5 0
3 years ago
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