The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
The sequence is arithmetic because the term is being multiplied by 5 each time
Answer:
The solution for y = -1.
Step-by-step explanation:
Given:
....(1)
....(2)
So, to solve for y, first we solve for x in equation (2):
⇒
Dividing both sides by 2,
⇒
Now, substituting the value of x in equation (1):
⇒
⇒
⇒
⇒
⇒
Dividing both sides by 11,
⇒
Therefore, the solution for y = -1.
Answer:
26.75 units ^2
Step-by-step explanation:
Since the shape is complex, divide it into 3 right angled triangles and one square. Find the area of these individual shapes first, then fin the sum of these area to calculate the ultimate area of e complex shape:
Triangle 1 = 1/2 x 2 x 5 = 5 units ^2
Triangle 2 = 1/2 x 2 x 2 = 2 units ^2
Triangle 3 = 1/2 x 3.5 x 9 = 15.75 units ^2
Square = 2 x 2 = 4 units squared.
Now add all these up 15.75 + 2 + 5 + 4 = 26.75 units squared.
Hope this helps
