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3 years ago

Solve for the following using long division 723 ÷ 4

Mathematics

2 answers:

nika2105 [10]3 years ago

8 0

Answer:

180.75

Step-by-step explanation:

723 ÷ 4

Digiron [165]3 years ago

5 0

So, the answer to this question using long division is 180, remainder 3.

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Adding fractions with unlike denominators

hodyreva [135]

Multiply the 3 times 4. Then do the same on the top.

8 0

3 years ago

There are 30 students in Mrs. Woodward’s class, and 1/5 of the class has their own cell phone. Of this group of students, 1/2 of

olga_2 [115]

Answer:

3 students

Step-by-step explanation:

There are 30 students in Mrs. Woodward’s class.

$\dfrac{1}{5}$ of the class has their own cell phone, so

$\dfrac{1}{5}\cdot 30=\dfrac{1}{5}\cdot \dfrac{30}{1}=6$

students have their own cell phones.

$\dfrac{1}{2}$ of those 6 students are allowed to use social media. So,

$\dfrac{1}{2}\cdot 6=\dfrac{1}{2}\cdot \dfrac{6}{1}=3$

students are allowed to use social media.

3 0

3 years ago

In your computation, approximate its value as 3.14.

andrey2020 [161]

Answer: d

Step-by-step explanation:

Find the area of the rectangle.

$A=l*w\\A=(15in)(12in)\\A=180in^2$

Find the area of the base of the semicircle.

$A=\pi r^2$

12 in would be the diameter, divide by 2 to get the radius.

$\frac{12}{2}=6$

Plug this into the formula.

$A=(3.14)(6)^2\\A=113.04in^2$

Since we do not have a full circle but a semi one instead, we must divide our result by 2.

$\frac{113.04}{2}=56.52in^2$

Add both areas.

180+56.52=236.52 $in^2$

7 0

3 years ago

How long is the segment from (-5, 2) to (-5,-8)?

Pavel [41]

Answer:

Step-by-step explanation:

8 0

3 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

2 years ago

Solve for the following using long division 723 ÷ 4​

Solve for the following using long division 723 ÷ 4