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2 years ago

10

You invest $5,000 in a savings account paying 4% interest compounded quarterly. How much is in the account after 5 years if ther

e are no withdrawals and no additions to the account?

2 answers:

Nezavi [6.7K]2 years ago

8 0

A=P(1+R)TIME
5000(1+0.04)^5
= 6083.264512
NOTE THE 5 IS WRITTEN AS A SQUARE

Hitman42 [59]2 years ago

3 0

1 years is $5200
2 years is $5408
3 years is $5624.32
4 years is $5849.29
5 years is $6083.26

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Schach [20]

Answer:

$\Huge\boxed{\mathsf{-153}}}$

Step-by-step explanation:

$\Large\boxed{\mathsf{LESSON: ORDER \quad OF \quad OPERATIONS}}}$

$\Large\boxed{\mathsf{SUBJECT: MATH}}}$

To use the order of operations stands for (Parenthesis, Exponents, Multiply, Divide, Add, and Subtract) from left to right.

First, do parenthesis.

17(-12+3)

(-12+3)=-9

17(-9)

Then, multiply.

17*9=153

17(-9)=-153

-153

$\Large\boxed{\mathsf{\Rightarrow -153}}$

The correct answer is -153.

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3 years ago

Choose the number phrase that correctly matches the word phrase “18 less 6.”

USPshnik [31]

It is 18-6 out of all the other ones

7 0

1 year ago

so, im t trying to find the original price and sale price of a book for example and the amount of discount is 2.80 dollars and t

aliya0001 [1]

Okay, so since the discount is 60% of the price and it comes out to $2.8, we are going to form the following expression, where x is the original price.

60% of x = 2.8

Simply means: 60/100 * x = 2.8

You solve for x, which comes out to $4, which is your original price.

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2 years ago

Given the line below. Write the point-slope form of the given line that passes through the points (0, 3) and (4, 0). Identify (x

jeka57 [31]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
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&&(~{{ 0}} &,&{{ 3}}~) 
% (c,d)
&&(~{{4}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
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\\\\\\
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4 0

3 years ago

a manufacturer of bicycle parts requires that a bicycle chain have a width of 0.3 inch with an absolute deviation of at most 0.0

quester [9]

Answer:

$|w-0.3| \leq 0.0003$

And solving we got:

$-0.0003 \leq w-0.3 \leq 0.0003$

$0.3-0.0003 \leq w \leq 0.3+0.0003$

$0.2997 \leq w \leq 0.3003$

Step-by-step explanation:

For this case we can define the following notation:

$W$ represent the width

And we want a maximum error of 0.0003 so we can set up the following equation:

$|w-0.3| \leq 0.0003$

And solving we got:

$-0.0003 \leq w-0.3 \leq 0.0003$

$0.3-0.0003 \leq w \leq 0.3+0.0003$

$0.2997 \leq w \leq 0.3003$

3 0

2 years ago