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2 years ago

I NEED HELP ASAP!!!!!

Mathematics

1 answer:

lara31 [8.8K]2 years ago

3 0

Answer:

W = 2.5d + 62

Step-by-step explanation:

The calf weighed 62 pounds when they were born. This gives us a base of 62 pounds - the calf cannot weigh less than 62 pounds and it does on day 0. On each day , the calf gains 2.5 pounds. We can times the number to days by 2.5 to get the gain from day 0. We can add these two values together to get the total current weight of the calf.

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Find the gradient of line segment AB A is point (-3,3) B is point(-1,-1)

Fynjy0 [20]

Answer:

$m=-2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Slope (Gradient) Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

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B (-1, -1)

Step 2: Find slope m

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2 years ago

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Arte-miy333 [17]

Answer:

Step-by-step explanation:

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1 year ago

Write the log equation as an exponential equation

Serjik [45]

Answer:

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Step-by-step explanation:

Tip: When $log_{a} b = c$ , $a^{c} =b$ is also true.

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2 years ago

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Tanya [424]

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1 year ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

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The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this question, we have that:

$\pi = 0.21$

90% confidence level

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How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when $M = 0.03$ . So