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den301095 [7]
3 years ago
13

The temperature at 6 AM what is -12°F the temperature increased by 1/2°F each hour for six hours what is the temperature in degr

ees Fahrenheit at noon
Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

1/2 degree x 6 hours = 3 degree increase.

-12 + 3 = -9

The temperature at noon was -9 degrees.

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Write an algebraic expression for: the quantity 2 plus 88y divided by 47
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Write and algebraic expression for the quantity 2 plus 88y divided by 47. Your answer would be D.
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2 years ago
Examine this right triangle. A right triangle has a side length of 16 meters and hypotenuse of 20 meters. Which equation can be
Sergeu [11.5K]

The equation can be used to find the missing leg in the triangle 20^{2} = 16^{2} +a^{2}.

<h3>What is the right triangle?</h3>

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse.

It is given that a right triangle has a side length of 16 meters and a hypotenuse of 20 meters.

From a Pythagoras theorem

b^{2} = c^{2} +a^{2} \\20^{2} = 16^{2} +a^{2}\\20^{2}-16^{2} =a^{2}\\a^{2} = 20^{2}-16^{2} \\

Thus, the equation can be used to find the missing leg in the triangle 20^{2}-16^{2} =a^{2}.

Learn more about the right-angle triangle;

brainly.com/question/5474676

3 0
2 years ago
Read 2 more answers
Please help I just need the height and area of the triangle 6th grade math
Vesna [10]

Answer:

It looks like you forgot to attach a picture.

Since I cannot answer you're question fully, it will not be a complete solution.

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5 0
3 years ago
What is 1 7/9 - 4/9?
Lera25 [3.4K]
1 7/9 - 4/9

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7 0
3 years ago
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To solve this, we have to find the volume of the cylinder first.  The formula to be used is V =  \pi  r^{2} h

Given:V= ?r= 6cmh= 10cm
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V= (3.14)(6cm)^{2} x 10cmV= (3.14)(36cm^{2}) x 10cmV= (113.04cm^{2}) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is.  Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
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The weight of the oil is 968.75 gm.
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3 years ago
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