Yo got to the calculator click scientific then click 9 the go to the left side where all the x's are then click the one that looks like the y is on the top right next to the x and then click 6 and then click enter and then you get 531441
If it is a single transformation, it will need to be a homothetic transformation.
None of the points remain at the old place, so it cannot be a scaling problem with respect to one of the existing points.
A homothetic transformation is bacically a scaling problem, with respect to an arbitrary point called the homothetic centre.
The centre, O, if it exists, is along the point joining any original point and the transformed point.
Here, take a pencil (imaginary one if you wish) and join points AA', BB', CC', DD', EE' and you will find that they are concurrent at point O (3,-6).
So O(3,-6) is the centre of homothety.
The scale factor, as usual, is AO/A'O, or BO/B'O... for transformation from X to Y (X is ABCDE), or the reciprocal if it is from Y to X.
Problem 5
Each two tangents form a right angle from the center of the circle to the circumference (a radius) and from the circumference to the exterior point. That makes a kite of 2 tangents and 2 radii.
The radii make an angle of 360 - 2*90 - 47 = 133.
That is also the central angle for the arc you are asking about.
Answer: 133.
Problem 9
The center is at point (-6, - 8) So far what you have is
(x + 6)^2 + (y + 8)^2 = r^2
You use the two given points to find r^2
r^2 = (x2 - x1)^2 + (y2 - y1)^2
r^2 = (-6 - 0)^2 + (- 8 - 0)^2
r^2 = 36 + 64
r^2 = 100
The circles equation is (x + 6)^2 + (y + 8)^2 = 100
Answer D
Answer:
theirs nothing to identify tho
Step-by-step explanation:
Answer:
((x * 7) - 4) = 8 + x
Step-by-step explanation:
X - is a number
if you need to solve it:
x * 3 = 8 +x
3x = 8 + x
2x = 8
~~(x=4)~~
Hope this helped
