Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
Answer:
Step-by-step explanation:
Answer:
-2a³+9a²+45a+6ab²+18b²
Step-by-step explanation:
(a+3)(-2a²+15a+6b²)
Distribute the a:
-2a³+15a²+6ab²
Then distribute the 3:
-6a²+45a+18b²
Now add both of the results together:
-2a³+15a²+6ab²-6a²+45a+18b²
Combine like terms:
-2a³+9a²+45a+6ab²+18b²
The answer is the second option given
18/10
9/5
Anything along those lines!
