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Yanka [14]
3 years ago
13

Please help with this question​

Mathematics
1 answer:
ioda3 years ago
3 0

Answer:

25

Step-by-step explanation:

\frac{5^8 \times 5^{-2}}{5^4}

\frac{5^{8+-2}}{5^4}

\frac{5^{6}}{5^4}

5^{6-4}

5^2

=25

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In the diagram below AQRS is an equilateral triangle and RT
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Answer:

The answer is D.

Step-by-step explanation:

AQRT is a 30-60-90 triangle.

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Which shape is similar to shape l?​
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Which of the following mixed numbers has a value between 10/3 and11/3
Paraphin [41]

The answer would be A


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following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in
valina [46]

<em>Note:</em> <em>As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.</em>

Answer:

The mode of the data = 75

Step-by-step explanation:

Lets visualize the given data in a table to show the frequency distribution:

<em>Daily expenditure on milk (in Rs)           Number of households</em>

<em>                  0-30                                                           5</em>

<em>                 30-60                                                          6        </em>

<em>                 60-90                                                          9</em>

<em>                 90-120                                                         6</em>

<em>                 120-150                                                        4</em>

Here the maximum frequency is 9.

So, modal class is <em>60-90.</em>

<em />

As the formula to calculate the mode:

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Here, the maximum

l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30

l= is the lower limit of the class

f_{1} = is the frequency of the modal class

f_{0} = is the frequency of the previous modal class

f_{2} = is the frequency of the next previous modal class

l= is the class size

So,

Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )

Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )

Mode = 60 + \frac{(30)(3)}{6}

Mode = 60 + 15=75

∴ The mode of the data = 75

<em>Keywords: mode, frequency distribution</em>

<em> Learn more about mode and frequency distribution from brainly.com/question/14354368</em>

<em> #learnwithBrainly </em>

5 0
3 years ago
If (x – 4) + 6 = 2 - (4 - 2x), then x =<br> A. -4<br> B. -2<br> C. 2<br> D. 4
blondinia [14]

Answer:

x=4

Step-by-step explanation:

Remove the parentheses and turn the 4-2x and make it into 4+2x candle the equal term -4 and should be left with x+6=2+2x then move the variable to the left and change the sign so it would be x-2x=2-6 and collect like terms so it would be -x=2-6 and then calculate that and get -x= -4

(sorry its alot)

6 0
4 years ago
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