Let u = x², then we would have u² + 5u - 6 = 0
From here, we can factor it and get us (u-1)(u+6) = 0
So our solution for u is u = -6 or 1.
Now substitute u back to x².
x² = -6 or 1
x = ±√(-6) or ±√1
Since ±√(-6) is not real number, we ignore it.
Which leave us x = ±√1 = <span>±1
So our real solution is x = -1 or 1.</span>
<h3>
Answer: Choice H) 2</h3>
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Explanation:
Recall that the pythagorean trig identity is 
If we were to isolate sine, then,

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.
Through similar calculations,
Cosine is also positive in this quadrant.
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So,

Therefore,

is an identity as long as 0 < x < pi/2
LCM= 40
factors of 5- 5, 10, 15, 20, 25, 30, 35, 40*
factors of 8- 8, 16, 24, 32, 40*
393/393 - 168/393 = 225/393
Simplify 225/393 by 3 because that is is the fractions GCF
75/131