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2 years ago

10

4x+2y=6 what is the x intercept of the given equation in standard form . Show your solving steps . Please help

1 answer:

nadya68 [22]2 years ago

3 0

Answer:

(1.5,0)

Step-by-step explanation:

The x intercept is where y=0

so we can just plug in 0 for y and solve for x

4x+2(0)=6

4x=6

x=6/4

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three boxes under my stairs contain apples or pears are both each box contains the same number of pieces of fruit the first box

Brrunno [24]

There are 16 fruits in each of the boxes found under the stairs.

<h3>What is an equation?</h3>

An equation is an expression used to show the relationship between two or more numbers and variables.

Let x represent the number of pears, hence:

Number of fruit in first box = 12 + (1/9)x

Number of fruit in second box = number of fruit in third box = (8/9)x ÷ 2 = (4/9)x

Therefore:

12 + (1/9)x = (4/9)x

x = 36

First box = second box = third box = (4/9) * 36 = 16

There are 16 fruits in each of the boxes found under the stairs.

Find out more on equation at: brainly.com/question/2972832

4 0

1 year ago

Simplify 8^x/4^y x 2^z

Lera25 [3.4K]

Answer:

The answer is 8x.

Step-by-step explanation:

It is 8x.

EXCEPT,

Is it $2^{z}$ or $2^{2}$

If it is $2^{z}$ then the answer is $\frac{2^{3x+z} }{4}$

PLEASE MARK BRAINLIEST

4 0

1 year ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

How do I do any of this?!

evablogger [386]

U should get the app "photomath" it will help u out alot!!!

7 0

2 years ago

Aha please help!!!!! im a bit confused lol

Stels [109]

Answer:

e : g = 2 : 7

Step-by-step explanation:

e/f = 3/7

e = 3f/7

f/g = 2/3

g = 3f/2

e/g = (3f/7)/(3f/2) = 2/7

3 0

2 years ago