A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as
0.30. which expression is the correct way to calculate the frequency of individuals that were heterozygous? A. (0.70)×(0.30) B. (0.70)-(0.30) C. 2×(0.70)×(0.30) D.2×(0.70-0.30)
