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iVinArrow [24]
2 years ago
8

A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as

0.30. which expression is the correct way to calculate the frequency of individuals that were heterozygous?
A. (0.70)×(0.30)
B. (0.70)-(0.30)
C. 2×(0.70)×(0.30)
D.2×(0.70-0.30)​
Biology
1 answer:
mylen [45]2 years ago
5 0

Answer:

this one

Explanation:

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The parents must be Tt, Tt

Explanation:

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This means that the parents must be Tt, Tt.

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