The ratio of sides for a 30 : 60 : 90 = 1 : √3 :2.
Note the 90 degrees represent the hypotenuse, which in this case is 30 inches.
<span>1 : √3 :2 = x : y : 30
</span>
To get 1, on the left side, we simply divide 2 by 2
Similarly x = 30/2 = 15.
To get √3, on the left side, we simply multiply 1 by √3
Similarly y = 15 * √3 = 15√3
<span>Therefore the length and width respectively are </span>15 and 15√3 inches<span> </span>
Answer:
4³
Step-by-step explanation:
Hope this helps!!
In the future, count the amount of same numbers you are multiplying:
5*5*5*5*5
there are 5 fives, so 5⁵
Answer:
![approx. = 85.28 {ft}^{2}](https://tex.z-dn.net/?f=approx.%20%3D%2085.28%20%7Bft%7D%5E%7B2%7D%20)
Step-by-step explanation:
You can think of this as adding the area of the rectangular portion of the deck (length x width) and the semicircular portion (πr^2)/2.
(l×w)+(πr^2)/2
(10×7)+((π2^2)/2
79+2π
![approx. = 85.28 {ft}^{2}](https://tex.z-dn.net/?f=approx.%20%3D%2085.28%20%7Bft%7D%5E%7B2%7D%20)
Answer:
![IQR= Q_3 -Q_1 = 130-100=30](https://tex.z-dn.net/?f=%20IQR%3D%20Q_3%20-Q_1%20%3D%20130-100%3D30)
We know that below the third quartile we have 75% of the values and below the first quartile we have 25% of the values. Then between the third and the first quartile we will have 75-25%=50% of the values.
And then we can apply the following proportion rule:
![\frac{354}{50} =\frac{x}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B354%7D%7B50%7D%20%3D%5Cfrac%7Bx%7D%7B100%7D)
And solving for x we got:
![x = 100 (\frac{354}{50})=708](https://tex.z-dn.net/?f=%20x%20%3D%20100%20%28%5Cfrac%7B354%7D%7B50%7D%29%3D708)
So then the total of students is approximately 708
Step-by-step explanation:
We know that 354 students are between 100 and 130 so then the interquartile range is:
![IQR= Q_3 -Q_1 = 130-100=30](https://tex.z-dn.net/?f=%20IQR%3D%20Q_3%20-Q_1%20%3D%20130-100%3D30)
We know that below the third quartile we have 75% of the values and below the first quartile we have 25% of the values. Then between the third and the first quartile we will have 75-25%=50% of the values.
And then we can apply the following proportion rule:
![\frac{354}{50} =\frac{x}{100}](https://tex.z-dn.net/?f=%20%5Cfrac%7B354%7D%7B50%7D%20%3D%5Cfrac%7Bx%7D%7B100%7D)
And solving for x we got:
![x = 100 (\frac{354}{50})=708](https://tex.z-dn.net/?f=%20x%20%3D%20100%20%28%5Cfrac%7B354%7D%7B50%7D%29%3D708)
So then the total of students is approximately 708