Answer:
I attached the work to your problem below.
I hope it helps.
Answer:
It would look like the picture I attached at the bottom.
Step-by-step explanation:
We know that the slope is -3 and the y intercept is (0,4) (plugging in 0 for x will get you that point), and then you can just graph an equation like you normally would, using rise/run to go down 3 units for every one unit you go right, and plugging in easy x values to check your work.
It gets a little tricky because the question then adds the inequality, and we see that y is now less than <em>or equal to </em>the original equation.
Since it is less than, we can shade all the values below the graph.
(Also, you should probably note for future reference that if it was just less than, the shading would look the same while the graph itself would be dotted because the values on the line are nor included in the solution set).
Desmos is a great website to use if you're having trouble graphing in the future :)
9514 1404 393
Answer:
- car value: $4,953.84
- population: 446
- maybe not
Step-by-step explanation:
All of these exponential function problems use the same equation, but with different plug-in values. These can be easily accommodated by a spreadsheet or graphing calculator.
The general form of the value after t years is ...
(initial value)×(1 +annual growth rate)^(years)
The growth rate is positive for an increase, negative for a decrease.
a) Initial value: 22385; growth rate: -0.14; years: 10
value after 10 years: $22385×(1-0.14)^10 = $4953.84
__
b) initial value: 290; growth rate: 0.09; years: 5
population after 5 years: 290(1+.09)^5 = 446
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c) initial value: $4000; growth rate: -0.10; years: 8
value after 8 years: $4000(1 -0.10)^8 = $1721.86
Selling the car for $1500 is selling it for <em>less than its estimated value</em>. That may not be a good decision.
_____
<em>Additional comment</em>
The property value of the car is not the only consideration when evaluating the sale. Other costs related to the car may come into play, and there may be tax implications.
The cross product of two vectors gives a third vector
that is orthogonal to the first two.
Normalize this vector by dividing it by its norm:
To get another vector orthogonal to the first two, you can just change the sign and use
.
22x3=66 then plug it into the problem
66÷11=6
so your answer is 6