Find A cup(B cap C) . A = \{1, 4, 6, 7\}; B = \{3, 4, 5\}; C = \{2, 4, 8\}; \{1, 4, 6, 7\} 4 } \{1, 2, 3, 4, 5, 6, 7, 8\}
Inessa05 [86]
The only common element between B and C is 4, so B ∩ C = {4}.
4 is also already contained in A, so B ∩ C is a subset of A, and thus
A U (B ∩ C) = A = {1, 4, 6, 7}
A' : -1, 3
B': 1, 2
C': 1, 5
Answer:
88
Step-by-step explanation:
33 plus 55
Answer:
-2<x≤5
Step-by-step :
-1<x+1≤6 So fisrt what every we do to one side we must do to the other. In this case it's a bit different since we are dealing with inequalities.
-1<x+1≤6 I would start off by isolating x in the middle.
-1<x+1≤6 I subtracted 1 from all three sides.
-1 -1 -1
Now your equation should look like this:
-2<x≤5 Now there is really nothing much we can do here since we were just trying to get x by its self.
Answer : -2<x≤5
Answer:
the answer for will be x≥-4
