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3 years ago

State the commutative property of addition using the variables a and b.

Mathematics

2 answers:

Verdich [7]3 years ago

7 0

Answer:

a+b=b+a

Step-by-step explanation:

so 7+4=12 and 4+7=12 so addition is commutative

larisa [96]3 years ago

4 0

Step-by-step explanation: To understand the commutative, let's look at the following problem.

2 + 3 = 3 + 2

The problem shown above demonstrates the commutative property of addition. In other words, the commutative property of addition says that changing the order of the addends does not change the sum.

For example here, we can easily see that the sum of 2 + 3 gives us 5 is equal to the sum of 3 + 2 which is also 5.

In more general terms, the commutative property of addition can be written as a + b = b + a where a and b are each variables that can represent any number.

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2 years ago

Perform the indicated operation and express the result as a simplified complex number. I need help with 35

skelet666 [1.2K]

Given:-

$\frac{3+4i}{2-i}$

To find:-

The simplified form.

At first we take conjucate and multiply below and above.

The conjucate is,

$2+i$

So now we multiply. we get,

$\frac{3+4i}{2-i}\times\frac{2+i}{2+i}$

Now we simplify. so we get,

$\frac{3+4i}{2-i}\times\frac{2+i}{2+i}=\frac{6+3i+8i+4(i)^2}{2^2-i^2}$

We know the value of,

$i^2=-1$

Substituting the value -1. we get,

$\begin{gathered} \frac{6+3i+8i+4(i)^2}{2^2-i^2}=\frac{6+3i+8i+4(-1)_{}^{}}{2^2-(-1)^{}} \\ \text{ =}\frac{6-4+11i}{2+1} \\ \text{ =}\frac{2+11i}{3} \end{gathered}$

So now we split the term to bring it into the form a+ib. so we get,

$\frac{2+11i}{3}=\frac{2}{3}+i\frac{11}{3}$

So the required solution is,

$\frac{2}{3}+i\frac{11}{3}$

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1 year ago