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3 years ago

What is the equation of the following direct variation?

Mathematics

2 answers:

siniylev [52]3 years ago

4 0

Answer:

y=-2x

Step-by-step explanation:

nataly862011 [7]3 years ago

3 0

Answer:

y=-2x

Step-by-step explanation:

Because, let us take (-1,2)

2=-2(-1)

2=2

Similarly all the points show the same.

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Someone please help!

Natalija [7]

The box plot shows the range and quartiles of the data. It does not show numbers or the mean. The only appropriate choice is

... The lower quartile for the data

3 0

3 years ago

Sole for y k = p/2(y+w) y =

mojhsa [17]

Answer:

Answer: y = (2k -pw)/p

Step-by-step explanation:

$k = \frac{p}{2} (y + w)$

multiply 2 on both sides:

$k \times 2 = 2 \times \frac{p}{2} (y + w) \\ \\ 2k = p(y + w)$

open the bracket:

$2k = py + pw$

subtract pw from both sides:

$2k - pw = (py + pw) - pw \\ 2k - pw = py$

divide p on both sides:

$\frac{2k - pw}{p} = \frac{py}{p} \\ \\ y = \frac{2k - pw}{p}$

4 0

3 years ago

Read 2 more answers

h(t)=-5t^2+10t+3 is the height of a diver above the water, t seconds after the diver leaves the springboard. How high above the

Kobotan [32]

Answer:

3 units

Step-by-step explanation:

So if we want to know how high the spring board is, this will need to be the time at which the diver is still at the top of the board, in this case t = 0 seconds.

So we will need to find h(0)

h(0) = 5(0)² + 10(0) + 3 = 0 + 0 + 3 = 3

5 0

3 years ago

Sum or products of 4x47

andrezito [222]

You multiply 4 and 47 so 188 would be the answer. Hope this helps! :)

4 0

3 years ago

Read 2 more answers

A surveyor standing on top of a cliff found that the angle of depression of a boat as sea is 22°. if the top of the cliff is 15m

Alex73 [517]

Answer:

From the photo above i interpreted the question and drew a triangle to make it easier to solve

Tan is used to solve the question as we were given opposite (as height of the cliff) and to find Adjacent ( the distance between the foot of the cliff to the boat)

Tan θ =Opp/Adj

Tan 22°=15/a

Cross Multiply

aTanθ=15°

Divide both sides by Tan 22

aTan22/Tan22 = 15/Tan 22

a = 15/Tan 22°

a = 37.13 m

Therefore the distance between the foot of the cliff to the boat is 37.13 metres

5 0

2 years ago