Answer:
The velocity is 7.0m/s
Explanation:
Given
![mass (m) = 1kg](https://tex.z-dn.net/?f=mass%20%28m%29%20%3D%201kg)
![height (h) = 2.5m](https://tex.z-dn.net/?f=height%20%28h%29%20%3D%202.5m)
![g = 9.8m/s^2](https://tex.z-dn.net/?f=g%20%3D%209.8m%2Fs%5E2)
Required
The bottom of the plane velocity
To do this, we apply the work-energy theorem which states that the energy at the highest point and at the lowest point are equal.
<u>At the highest point</u>
![v = 0](https://tex.z-dn.net/?f=v%20%3D%200)
![E = \frac{1}{2}mv^2 + mgh](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%2B%20mgh)
![E = \frac{1}{2}*1*0^2+ 1 * 9.8 * 2.5](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A1%2A0%5E2%2B%201%20%2A%209.8%20%2A%202.5)
![E = 0 + 24.5](https://tex.z-dn.net/?f=E%20%3D%200%20%2B%2024.5)
![E = 24.5](https://tex.z-dn.net/?f=E%20%3D%2024.5)
<u>At the lowest point</u>
![h = 0](https://tex.z-dn.net/?f=h%20%3D%200)
![E = \frac{1}{2}mv^2 + mgh](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%2B%20mgh)
![E = \frac{1}{2} * 1 * v^2 + mg(0)](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%201%20%2A%20v%5E2%20%2B%20mg%280%29)
![E = \frac{1}{2} * 1 * v^2 + 0](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%201%20%2A%20v%5E2%20%2B%200)
![E = \frac{v^2}{2}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bv%5E2%7D%7B2%7D)
Equate both values of energy
![24.5 = \frac{v^2}{2}](https://tex.z-dn.net/?f=24.5%20%3D%20%5Cfrac%7Bv%5E2%7D%7B2%7D)
![v^2 = 2 * 24.5](https://tex.z-dn.net/?f=v%5E2%20%3D%202%20%2A%2024.5)
![v^2 = 49](https://tex.z-dn.net/?f=v%5E2%20%3D%2049)
Take square roots of both sides
![v = 7](https://tex.z-dn.net/?f=v%20%3D%207)
The velocity is 7.0m/s
D. American Council on Education
Hope this helps :)
High and low tides are caused by the Moon. The Moon's gravitational pull generates something called the tidal force. The tidal force causes Earth—and its water—to bulge out on the side closest to the Moon and the side farthest from the Moon. These bulges of water are high tides.