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valina [46]
2 years ago
9

Two ordered pairs that are located exactly six units from (2, -3).

Mathematics
1 answer:
myrzilka [38]2 years ago
3 0
Can you put a picture of the graph?
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PLS HELP ME ON THIS YOU CAN DO ALL THE QUESTIONS PLSSSS
Ivahew [28]

Answer:

The first is  \frac{4}{10}

The second is \frac{10}{16}

The third is \frac{3}{10}

The fourth is \frac{6}{21}

The fifth is \frac{3}{5}

5 0
2 years ago
determine the quadratic function of f whose graph is given. The vertex is (1,-3) and the y-intercept is -2
LuckyWell [14K]
Hmmm the y-intercept is at -2?  what does that mean?  well, is where the graph "intercepts" or touches the y-axis, and when that happens, x = 0, so the point is really ( 0 , -2 ).

and we know where the vertex is at.  Let's assume a vertical parabola, in which case the squared variable is the "x".

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=1\\
k=-3
\end{cases}\implies y=a(x-1)^2-3
\\\\\\
\textit{now, we also know that }
\begin{cases}
x=0\\
y=-2
\end{cases}\implies -2=a(0-1)^2-3
\\\\\\
1=a(-1)^2\implies \boxed{1=a}\qquad thus\implies 
\begin{cases}
y=1(x-1)^2-3\\
\textit{or just}\\
y=(x-1)^2-3
\end{cases}
6 0
3 years ago
Explain how to find the absolute value of a number.
kykrilka [37]
The correct answer is C. Absolute numbers should always yield a positive value. Other choices doesn’t do that. Measuring the distance on a number line ensures the positive value without changing the magnitude of the number given.
5 0
1 year ago
Find the midpoint of the line segment joining the points. (6, -5), (6, 3)
adoni [48]

Answer:

The mid point is (6,-1)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Independent variable
amm1812

Answer:

The variable that you control, often referred to as the x.

7 0
2 years ago
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