Answer:
The graph should be stretched rather than become narrower.
Step-by-step explanation:
To figure this out, just create some example points.
At x = 0, your y-value will always be 0. But if you were to plug in the value 1, you would get a y-value of 1 in y=x^2, but a value of 0.5 in y=0.5x^2. If you were to plug in a value of 2, you would get a value of 4 in y=x^2, but a value of 2 in y=0.5x^2.
If you continue this pattern for a few more points, then plot them, you will see that adding a coefficient of 0.5 simply stretches the graph
Answer:
475767u5yttuyy
Step-by-step explanation:
phobrovicodibfofiffivonf
Answer:
D. (25π - 50) sq m
Step-by-step explanation:
Since ABCD is a square with the area of 100, we know that the dimensions are 10 by 10. With that, we can find that triangle ABC = 50 sq m because of (h*l)/2. Since A is the center of the circle that contains arc BD, we know that 10 is the radius of the quarter-circle ABC. Using (πr^2)/4 to get the area of the quarter-circle, we get that the quarter-circle ABC = 25π sq m. But the original triangle ABC in the quarter-circle is not shaded. Therefore, we subtract 50 from 25π, which leads to (25π - 50) sq m.
I hope this helped! :D
Answer:
Step-by-step explanation:
Ok first multiply the first two monomials:
Then multiply THAT with the OTHER monomial:
This should be the answer. Let me know if it's wrong.
Answer:
y = 6x + 22
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Slope Formula: 
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-3, 14)
Point (-1, 16)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute:
- Subtract/Add:
- Divide:
<u>Step 3: Find y-intercept </u><em><u>b</u></em>
- Define: y = 6x + b
- Substitute: 16 = 6(-1) + b
- Multiply: 16 = -6 + b
- Isolate <em>b</em>: 22 = b
- Rewrite: b = 22
<u>Step 4: Write linear equation</u>
y = 6x + 22
