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ira [324]
2 years ago
13

ERROR ANALYSIS Describe and correct the error in

Mathematics
1 answer:
valkas [14]2 years ago
3 0

Answer:

The graph should be stretched rather than become narrower.

Step-by-step explanation:

To figure this out, just create some example points.

At x = 0, your y-value will always be 0. But if you were to plug in the value 1, you would get a y-value of 1 in y=x^2, but a value of 0.5 in y=0.5x^2. If you were to plug in a value of 2, you would get a value of 4 in y=x^2, but a value of 2 in y=0.5x^2.

If you continue this pattern for a few more points, then plot them, you will see that adding a coefficient of 0.5 simply stretches the graph

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In her metalwork class, Anja cut a square of
Paul [167]

Given:

Anju cut square of tin, of edge 3.7 cm, from a larger square of edge 6.3 cm.

To find:

The area of the remaining tin.

Solution:

Area of a square is:

Area=a^2

Where, a is the edge of the square.

Area of the smaller square is:

A_1=(3.7)^2

A_1=13.69

Area of the larger square is:

A_2=(6.3)^2

A_2=39.69

The area of the remaining tin is:

A=A_2-A_1

A=39.69-13.69

A=26

Therefore, the area of the remaining tin is 26 sq. cm.

8 0
3 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a standard deviation of 1.5 and a mean diameter of 205
Crank

Answer:

P(205-0.3=204.7

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

Step-by-step explanation:

Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info

Where \mu=205 and \sigma=1.5

We can begin finding this probability this probability

P(205-0.3=204.7

For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z scores for each limit and we got:

z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778

z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778

So we can find this probability:

P(-1.778

And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:

P = 1-0.9243 = 0.0757

6 0
3 years ago
7/10 of the cakes at the bakery have flower on it. What is this number written a decimal?
tiny-mole [99]

Answer: the answer would be 0.7

Step-by-step explanation: i hope this helped

6 0
4 years ago
Read 2 more answers
. A spinner contains numbers 1-20. What
alexira [117]

Answer:

6/30 for a multiple of 3 and 4/20 for a multiple of 5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If Sarah drives 55 miles per hour, how long will it take her to drive from<br> Amityville to Denton?
Bess [88]

Answer:

29.5 hours

Step-by-step explanation:

Amityville to Denton is 1625 miles.

Since we know that Sarah drives at 55 mph we can divide 1625/55 and get 29.45454... and I assume that they want it rounded so it will be around 29.5 hours

8 0
3 years ago
Read 2 more answers
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