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ira [324]
2 years ago
13

ERROR ANALYSIS Describe and correct the error in

Mathematics
1 answer:
valkas [14]2 years ago
3 0

Answer:

The graph should be stretched rather than become narrower.

Step-by-step explanation:

To figure this out, just create some example points.

At x = 0, your y-value will always be 0. But if you were to plug in the value 1, you would get a y-value of 1 in y=x^2, but a value of 0.5 in y=0.5x^2. If you were to plug in a value of 2, you would get a value of 4 in y=x^2, but a value of 2 in y=0.5x^2.

If you continue this pattern for a few more points, then plot them, you will see that adding a coefficient of 0.5 simply stretches the graph

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85,110,x,120,120 : find the value of x
fomenos

The sum of angles of a pentagon is 540°, so x must be chosen to make that so.

85 + 110 + x + 120 + 120 = 540

540 -435 = x = 105

_____

The formula usually used to find the degree measure of the internal angles of an n-sided polygon is (n -2)·180°. For n=5, this is 3·180° = 540°.

6 0
4 years ago
Read 2 more answers
What is the length of EF?
Diano4ka-milaya [45]

The length of EF is 3.8

<h3>How to solve for EF?</h3>

To do this, we make use of the following law of sines

EF/sin(D)= DE/sin(F)

So, we have:

EF/sin(75)= 3/sin(50)

This gives

EF = sin(75) * 3/sin(50)

Evaluate the product

EF = 3.8

Hence, the length of EF is 3.8

Read more about law of sines at:

brainly.com/question/4372174

#SPJ1

6 0
2 years ago
Show work and show answer as a mixed number for 6x+11-16x=-21
kondaur [170]
6x + 11 - 16x = -21
6x-16x = -32
-10x = -32
x = -32/-10
x = 3.2
4 0
3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

8 0
4 years ago
If y varies inversely as x and k = 8, find x when y = 8.<br><br> 1<br> 8<br> 64
ankoles [38]
The answer is 1

<span>y varies inversely as x:
y = k/x

We have:
k = 8
y = 8
x = ?

y = k/x
x = k/y
x = 8/8
x = 1</span>
7 0
4 years ago
Read 2 more answers
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