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2 years ago

ERROR ANALYSIS Describe and correct the error in

Mathematics

1 answer:

valkas [14]2 years ago

3 0

Answer:

The graph should be stretched rather than become narrower.

Step-by-step explanation:

To figure this out, just create some example points.

At x = 0, your y-value will always be 0. But if you were to plug in the value 1, you would get a y-value of 1 in y=x^2, but a value of 0.5 in y=0.5x^2. If you were to plug in a value of 2, you would get a value of 4 in y=x^2, but a value of 2 in y=0.5x^2.

If you continue this pattern for a few more points, then plot them, you will see that adding a coefficient of 0.5 simply stretches the graph

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The archery club competed in a tournament. Each archer shot 6 arrows in 5 minutes.

stira [4]

Answer:

Step-by-step explanation:

8 0

1 year ago

Read 2 more answers

35g = 5<br> 15s = 120<br> 2 questions

Lubov Fominskaja [6]

Step-by-step explanation:

35g=5 g=1/7

15s=120 s=8

6 0

4 years ago

This is a variation acitivity:

sergey [27]

$\bf \qquad \qquad \textit{direct proportional joint variation} \\\\ \textit{\underline{y} varies jointly with \underline{x} and \underline{z}}\qquad \qquad y=kxz\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \stackrel{\textit{\underline{I} varies jointly with \underline{P} and \underline{t}}}{I=kPt} \\\\\\ \textit{we also know that } \begin{cases} P=2000\\ t=4\\ I=320 \end{cases}\implies 320=k(2000)(4)\implies \cfrac{320}{(2000)(4)} \\\\\\ 0.04=k\qquad therefore\qquad \boxed{I=0.04Pt} \\\\\\ \textit{if P=5000 and t=7, what is \underline{I}?}\qquad I=0.04(5000)(7)\implies I=1400$

8 0

3 years ago

HELP!<br> Which is the inverse of this matrix?

malfutka [58]

Answer:

$\text{\bf{A.}}\qquad\left[\begin{array}{ccc}-19&9&-7\\15&-7&6\\-2&1&-1\end{array}\right]$

Step-by-step explanation:

Many scientific and graphing calculators will compute this easily.

The inverse of a square matrix is a square matrix of the same dimensions. That eliminates choices C and D. We can check choices A and B by computing a couple of terms of the product of the given matrix and its "inverse". That product should be the identity matrix, with 1 on the diagonal and 0 elsewhere.

Using matrix A,

(r, c) = (1, 1) = 1(-19) +2(15) +5(-2) = -19 +30 -20 = 1 . . . . correct

(r, c) = (2,3) = 3(-7) +5(6) +9(-1) = -21 +30 =9 = 0 . . . . correct

Using matrix B,

(r, c) = (1, 1) = 1(-19) +2(-2) +5(15) = -19 -4 +75 = 52 . . . . incorrect

Indications are that choice A is appropriate.

7 0

3 years ago

A rectangle has a side length of 2x and a diagonal of 8x. What is the missing lenght?

Leona [35]

Answer:

2x $\sqrt{15}$

Step-by-step explanation:

we can use the Pythagorean Theorem to find the missing side (a):

a² + (2x)² = (8x)²

a² + 4x² = 64x²

a² = 60x²

a = √60x²

a = $\sqrt{4}$ · $\sqrt{15}$ · $\sqrt{x^2}$

This can be simplified to be 2x $\sqrt{15}$

6 0

3 years ago