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Anika [276]
3 years ago
14

Can someone help me? this is extremely important for me to complete!

Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

Answer:

Question 1: A,B,D,F

Queation2: the order is 2,3,1

Question3:A

Question4:A

Step-by-step explanation:

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10 points!!! What is sqr root 12x^8/ sqr root 3x^2 in simplest form
marta [7]

Answer:

2 x^3

Step-by-step explanation:

sqrt(12 x^8)/ sqrt(3x^2)

combine into 1 term

sqrt(12x^8/3x^2)

when dividing exponents with the same base, we subtract

sqrt(12/3  x^(8-2))

sqrt(4 x^6)

sqrt(4)  sqrt(x^6)

2 x^3

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2 years ago
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Convert the decimal to a fraction in simplest form. 0.25 =
Yuliya22 [10]
The answer in simplest form is 1/4.
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3 years ago
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Cubed root x cubed root x2​
Yuki888 [10]

Answer:

Final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

Step-by-step explanation:

Given problem is \sqrt[3]{x}\cdot\sqrt[3]{x^2}.

Now we need to simplify this problem.

\sqrt[3]{x}\cdot\sqrt[3]{x^2}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}

Apply formula

\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}

so we get:

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}

\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x

Hence final answer is \sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x.

7 0
3 years ago
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He made $ 394.90 because you need to add all the large paintings then the small ones then add them all
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