Answer:
11?
Step-by-step explanation:
A fit the first one and B for the second one
1 to 3
2 to 6
3 to 9
4 to 12
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Answer:
A and C
Step-by-step explanation:
I just answered the question.
<u>ANSWER</u>
The zeros are ![x=-5,x=0,x=5](https://tex.z-dn.net/?f=x%3D-5%2Cx%3D0%2Cx%3D5)
EXPLANATION
Given;
.
We can rewrite the function as
![f(x)=x^2(x^2-25)](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2%28x%5E2-25%29)
![\Rightarrow f(x)=x^2(x^2-5^2)](https://tex.z-dn.net/?f=%5CRightarrow%20f%28x%29%3Dx%5E2%28x%5E2-5%5E2%29)
![\Rightarrow f(x)=x^2(x-5)(x+5)](https://tex.z-dn.net/?f=%5CRightarrow%20f%28x%29%3Dx%5E2%28x-5%29%28x%2B5%29)
The zeros are found by equating the function to zero.
![\Rightarrow x^2(x-5)(x+5)=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2%28x-5%29%28x%2B5%29%3D0)
![\Rightarrow (x-5)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-5%29%3D0)
The multiplicity is 1, since it is odd the graph crosses at this intercept. which is ![x=5](https://tex.z-dn.net/?f=x%3D5)
Or
![\Rightarrow (x+5)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x%2B5%29%3D0)
The multiplicity is 1, since it is odd the graph crosses at this intercept. which is ![x=-5](https://tex.z-dn.net/?f=x%3D-5)
Or
![\Rightarrow x^2=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2%3D0)
This last root has a multiplicity of 2.
That is
repeats two times.
Since the multiplicity is even, the graph touches the x-axis at the point
.
See graph.