Answer:
The answer is x=24.
Step-by-step explanation:
This is a one step equation, so it is simple, as shown.
In order to isolate the variable, you need to multiply each side of the equation by the fraction's reciprocal. In this case, it is -4/5.
Thus, x= -30 x -4/5
All things said, the answer is x=24.
I hope this helped!!
~ Penny
<u><em>The total number of red counters that are in the box is; 728 red counters</em></u>
- We are told that the box contains 1079 counters.
Let the number of white counters be x.
Let the number of red counters be y.
Let the number of black counters be z.
Thus;
z:x = 2:7
Thus; 2x/7 = z
Also, we are given;
x:y = 3:8
Thus;
8x/3 = y
- Since total number in the box is 1079,then;
x + y + z = 1079
x + (8x/3) + (2x/7) = 1079
Multiply through by 21 to get;
21x + 56x + 6x = 22659
83x = 22659
x = 22659/83
x = 273
2x/7 = z
Thus; z = 2 × 273/7
z = 78
8x/3 = y
y = 8 × 273/3
y = 728
273 white counters
728 red counters
78 black counters.
Read more at; brainly.com/question/11712611
5 and 3 are two primary numbers for this question
Answer:
the factor of 12 is 1 2 3 4 6 12 so that
-3(n+4)
Aw yis
take the coefients and put them in rows
![\left[\begin{array}{ccc}4&5&|-7\\3&-6&|24\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%265%26%7C-7%5C%5C3%26-6%26%7C24%5Cend%7Barray%7D%5Cright%5D%20)
divide 2nd row by 3
![\left[\begin{array}{ccc}4&5&|-7\\1&-2&|8\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%265%26%7C-7%5C%5C1%26-2%26%7C8%5Cend%7Barray%7D%5Cright%5D%20)
multiply 2nd row by -4 and add to top one
![\left[\begin{array}{ccc}0&13&|-39\\1&-2&|8\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2613%26%7C-39%5C%5C1%26-2%26%7C8%5Cend%7Barray%7D%5Cright%5D%20)
divide top row by 13
![\left[\begin{array}{ccc}0&1&|-3\\1&-2&|8\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%26%7C-3%5C%5C1%26-2%26%7C8%5Cend%7Barray%7D%5Cright%5D%20)
multiply top row by 2 and add to bottom row
![\left[\begin{array}{ccc}0&1&|-3\\1&0&|2\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%26%7C-3%5C%5C1%260%26%7C2%5Cend%7Barray%7D%5Cright%5D%20)
x=2
y=-3
