Step-by-step explanation:
3 x^3-15x^2+18x 3(x^3-5x^2+6x)
First, we are going to find the radius of the yaw mark. To do that we are going to use the formula:

where

is the length of the chord

is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so

and

. Lets replace those values in our formula:




Next, to find the minimum speed, we are going to use the formula:

where

is <span>drag factor
</span>

is the radius
We know form our problem that the drag factor is 0.2, so

. We also know from our previous calculation that the radius is

, so

. Lets replace those values in our formula:



mph
We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was
13.34 miles per hour.
Answer:dudjdjdjdjdjdjdjdjdjdjdjdjdjdjdiidjdjdjdjd
Step-by-step explanation:
For the first is 3864
The second is 1320
A=3.14(which is pie) x 20.5^2
A=420x pie
A=1320
For the third is 2544
3864-1320=2544
Sorry if this is wrong too.
Answer:
169 Pounds
Step-by-step explanation:
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