We can use algebra.
So, what rate time 1.20 = .80
Let x = the rate (in a decimal form)
1.20x = .80
x = .6666666666
Now, we need to multiply by 100 to get a percentage.
66.66 The price is 66% of the regular price.
They marked it off
33.33%
Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get


Hence amount owed at the end of 1 year is 3640
Answer:
Step-by-step explanation:
o,o is in the origin
2(a+3) + 3(2a-1)
First, let's use the distributive property to expand 2(a+3):
2(a+3) = 2*a + 2*3 = 2a + 6
Let's use the distributive property now to expand 3(2a-1):
3(2a - 1) = 3*2a - 3*1 = 6a - 3
So 2(a+3) + 3(2a-1) = 2a + 6 + 6a - 3
Now you calculate variables between each others, and numbers between each others:
2a + 6 + 6a - 3 = 2a + 6a + 6 - 3 = 8a + 3
So the simplified form of 2(a+3) + 3(2a-1) is 8a + 3.
Hope this Helps! :)