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3 years ago

Find x Help me plz!!!

Mathematics

2 answers:

mariarad [96]3 years ago

3 0

9514 1404 393

Answer:

x = 8

Step-by-step explanation:

Assuming the figure is a parallelogram, the diagonals bisect each other. That means ...

3x -11 = x +5

2x = 16 . . . . . . . add 11-x to both sides

x = 8 . . . . . . divide by 2

Afina-wow [57]3 years ago

3 0

Answer:

the answer is x=8

Step-by-step explanation:

:)))))

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I need help on this I am just going to use the picture

Radda [10]

Answer:

Step-by-step explanation:

let y = f(x), that is

y = $\frac{2x-3}{5}$

Rearrange making x the subject

Multiply both sides by 5

5y = 2x - 3 ( add 3 to both sides )

5y + 3 = 2x (divide both sides by 2 ) , then

x = $\frac{5y+3}{2}$

Change y back into term of x, hence

$f^{-1}$ (x) = $\frac{5x+3}{2}$ → D

4 0

2 years ago

Read 2 more answers

In a newspaper, it was reported that the number of yearly robberies in Springfield in

scoundrel [369]

Answer:

32 robberies

Step-by-step explanation:

To find the amount here, divide 64 by 2 (or multiply by 1/2).

64 / 2

How many times does 2 go into 6? (3)

4 / 2

How many times does 2 go into 4? (2)

32 robberies

7 0

3 years ago

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

5 0

3 years ago

Pleaseeeeeeeee help me :)

Korolek [52]

Answer:

f(x) = 5 - x has a negative slope.

Step-by-step explanation:

Y = mx + c is the general form for a straight line.

Whem m is negative the slope is negative

Consider f(x) = 5 - x

f(x) = -x + 5

- so the slope is negative.

For g(x) we see that g(x) increases with x so the slope id positive.

8 0

2 years ago

Please help me asap. picture is linked

ozzi

Answer:

(4,-2)

Step-by-step explanation:

you just need to move from point P to 5 units to the right and 7 units down

7 0

2 years ago