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olga2289 [7]
2 years ago
11

There are 112 seats in the school auditorium. There are 7 seats in each row. There are 70 people seated, filling up full rows of

seats. How many rows are empty?
Mathematics
1 answer:
MatroZZZ [7]2 years ago
5 0
112 Seats/ 7 Seats= 16 Total Rows
70Seats / 7Seats = 10 Full Rows
16-10=
6 Remaining Rows that tell us that there are a total of 42 empty seats. 
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What integer is closest to <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B321%7D%20" id="TexFormula1" title=" \sqrt{321} " a
crimeas [40]

Answer:

Step-by-step explanation:

18*18 = 324

So 18 is the closest integer to \sqrt{321}

6 0
2 years ago
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Order 34x10^2, 1.2x10^7, 8.11x10^-3 and 435 from least to greatest.
GREYUIT [131]
8.11 x 10^-3
435
34 x 10^2
1.2 x 10^7
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2 years ago
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Write the definition of midpoint, provide a supporting figure
givi [52]

Step-by-step explanation: Using the diagram shown which I have provided in the image attached, the definition of a midpoint states that M is the midpoint of segment LN, then segment LN ≅ to MN.

The definition of a midpoint can also be stated the other way around. using the diagram shown, if segment LN ≅ to segment MN, then M is the midpoint of segment LN.

We can use hash marks in the figure to show that are 2 segments are congruent.

5 0
3 years ago
Tony took a city bus from his dorm to the school library, and then to a gym for a workout
Feliz [49]

Answer:

27 miles.

Step-by-step explanation:

Here I attach the draw of the coordinates.

Tony traveled 3 segments. The first was from (12,6) to (12, 15), where, leting 12 constant, he moved from 6 to 15 in the ordinates axis, which implies 9 units. This is the section 1 in the draw.

Then he moved from point B to C. If you notice, this distance is the hypotenuse on the the triangle DBC. We can find this value using Pitagoras' theorem:

DB^2 + CD^2 = CB^2

With DB=15 and CD=8 (12 minus 4 = 8)

15^2 + 8^2 = 289

So CB^2=289

Applying sqr root:

CB = 17

So, the second section has a measure of 17 units.

Finally, the 3rd section is the hypotenuse of the DAC triangle and we can use Pitagoras to solve it:

CD^2 + AD^2 = CA^2

8^2 + 6^2 = CA^2

64 + 36 = 100

So, CA=10

In the 3r section we traveled 10 units.

So, in total he traveled 10 + 17 + 9 = 36 units

As every unit is 0.75 miles he traveled 36*0.75 miles:

36*0.75 = 27 miles

He traveled in total 27 miles!!

6 0
3 years ago
Will someone please help me understand this?
mario62 [17]

Option A:

The length of diagonal JL is 3 \sqrt{5} \text { units }.

Solution:

In the quadrilateral, the coordinates of J is (1, 6) and L is (7, 3).

So that, x_1=1, y_1=6, x_2=7, y_2=3

To find the length of the diagonal JL.

Using distance formula:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

d=\sqrt{(3-6)^2+(7-1)^2}

d=\sqrt{(-3)^2+(6)^2}

d=\sqrt{9+36}

d=\sqrt{45}

d=\sqrt{3^2\times 5}

d=3\sqrt{ 5} units

The length of diagonal JL is 3 \sqrt{5} \text { units }.

Option A is the correct answer.

7 0
2 years ago
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