The probability that the aircraft is overloaded is 0.6141; since this is a greater than 50% chance, the pilot should either reduce the number of passengers on the plane or require them to reduce their baggage.
The z-score for this is given by
z = (X-μ)/σ = (169-180.2)/38 = -11.2/38 = -0.29.
Using a z-table (http://www.z-table.com) we see that the probability of weights being less than this (the area to the left of this score) is 0.3859; to find the probability that the weight is greater than this (to the right), we subtract from 1:
1-0.3859 = 0.6141.
Answer:
Step-by-step explanation:
The formula of a distance between two points:
We have the points (1, -5) and (-3, 6). Substitute:
Answer:
You need $7.09
Step-by-step explanation:
Ex1. 100-92.91=7.09
Ex2. 92.91+7.09=100
So 4 hours for 40 dresses.
1 hour would be 40/4=10 dresses
50 dress = 1hr x 5 = 5 hrs#
