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kipiarov [429]
3 years ago
12

Tony weighs his pet turtle on a scale in his bathroom. The turtle weighs 6 1/4 ​ pounds. His turtle weighed 3 1/6 ​ pounds when

he first got him. About how much more does his turtle weigh now?
Mathematics
1 answer:
kodGreya [7K]3 years ago
4 0
3 1/12. Find the lowest common denominator. Multiply the the numerator and denominator by that. Then simplify.
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Evaluate the function.<br> f(x) = –22 – 9x + 20<br> Find f(9)
Alenkasestr [34]

Answer:

f(9)=-22-9(9)+20=-83

Step-by-step explanation:

f(9) means x = 9, Just substitute 9 into the function.

-9(9) = -81

-22-81+20 = -83

8 0
2 years ago
Which two statements below are true ?
Marrrta [24]
A) 2/6 = 1/3
1/3 = 1/3

True 

------

b) 1/3 > 2/4
1/3 > 1/2 

False
------

c) 1/8 > 3/4

False
------

d) 2/5 < 1/2

True
------

e) 4/12 < 1/6

False
------

f) 3/5 = 7/10

False
------

This is all just a process of simplifying fractions down.

The only 'true' statements there are is option A and D.
6 0
3 years ago
Select the correct answer. Simplify the expression.<br> (see the screenshot)
Sliva [168]

Answer:

Option D

Step-by-step explanation:

Given expression has been given as,

\sqrt[5]{224x^{11}y^8}

\sqrt[5]{224x^{11}y^8}=\sqrt[5]{2\times 2\times 2\times 2\times 2\times 7(x^{11})(y^8)}

                 =\sqrt[5]{(2^5)\times (7)(x^{10}\times x)(y^5\times y^3)}

                 =2^{\frac{5}{5}}\times 7^{\frac{1}{5}}\times x^{\frac{10}{5}}\times x^{\frac{1}{5}}\times y^{\frac{5}{5} }\times y^{\frac{3}{5} }

                 =2\times 7^{\frac{1}{5}}\times x^2\times y\times x^{\frac{1}{5} }\times y^{\frac{3}{5} }

                 =2x^2y\sqrt[5]{7xy^3}

Option D will be the answer.

7 0
3 years ago
What is the domain of the function below? {(0,2),(3,1),(5,2),(8,4)}
SCORPION-xisa [38]
They are all the x points on the graph like the range is the y
5 0
2 years ago
polynomial function of degree 4 with -1 as a zero of multiplicity 3 and 0 as a zero of multiplicity 1
iren [92.7K]
\bf \begin{cases}&#10;x=-1\implies &x+1=0\\&#10;x=0\implies &x=0&#10;\end{cases}&#10;\\\\\\&#10;\stackrel{\textit{multiplicity of 3}}{(x+1)^3}~~\stackrel{\textit{multiplicity of 1}}{(x)^1}=\stackrel{original~polynomial}{0}&#10;\\\\\\&#10;(x^3+3x^2+3x+1)(x)=\stackrel{y}{0}\implies x^4+3x^3+3x^2+x=y
6 0
3 years ago
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