The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for
is 9.
Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and
for 8<t<11.
A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.
B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.
C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.
D) In this we have to find the function at
when m belongs to
the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.
Learn more about functions at brainly.com/question/10439235
#SPJ10
Answer:
i think 1/300
Step-by-step explanation:
After solving I have come up with 6 2/9 or 6.22222.
3x-4y=65
3x=65+4y
x=(65+4y)/3, when y=4
x=(65+4*4)/3
x=(65+16)/3
x=81/3
x=27
X^2 - x - 90 =0
This equation is in standard form ax^2+ bx + c
The sum of the solutions is -b/a (a and b are the coefficients from the equation above, not the solutions to the equation)
The answer is 1/1 = 1