I need halp asap!!!!

PLEASE HELP!!! EASY POINTS

SOVA2 [1]

Answer: 50 x

Step-by-step explanation:

4 0

3 years ago

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Help fast how can I get to 1 bottle of paint???

Arisa [49]

Answer:

40 red, 48 yellow.

Step-by-step explanation:

So in your orange paint, the ratio of red paint to yellow paint is 2/3 : 4/5, we can simplify that to 2/3 (15) : 4/5 (15) ---> 10 : 12 ---> 5 : 6. So for every 5 parts of red paint, you need 6 parts of yellow paint. One part can be any amount, as long as all parts are equal. So together you need 5+6=11 parts. Lets divide 88 by 11 to get what one part is. 88/11=8, so in this case one part equals to 8 bottles. And remember you need 5 parts of red paint, so 5*8=40 bottles of red paint altogether, and 6 parts of yellow paint, so 6*8=48 bottles of yellow paint altogether to make your 88 bottles of orange pain.

Check: 40 bottles of paint + 48 bottles of paint will give you 88 bottles of paint in the end, so that is correct. 40 : 48 is also equal to 2/3 : 4/5 if you simplify them, so the ratio is also correct.

4 0

3 years ago

This should be a very simple question on interior angles adding up to 180º, however, I'm continuously getting it wrong. Help!

myrzilka [38]

Answer:

58°

Step-by-step explanation:

65°+57°=122°

180°-122°=58°

5 0

2 years ago

(b) how many measurements must be averaged to get a margin of error of ±0.0001 with 98% confidence? (round your answer up to the

goblinko [34]

Given that the scale readings of the laboratory scale is normally distributed with an unknown mean and a standard deviation of 0.0002 grams.

Part A:

If the weight is weighted 5 times and the mean weight is 10.0023 grams, the 98% confidence interval for μ, the true mean of the scale readings is given by:

$98\% \ C. \ I.=\bar{x}\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right) \\ \\ =10.0023\pm2.33\left(\frac{0.0002}{\sqrt{5}}\right) \\ \\ =10.0023\pm2.33(0.000089) \\ \\ =10.0023\pm0.00021 \\ \\ =(10.0023-0.00021, \ 10.0023+0.00021) \\ \\ =(10.0021, \ 10.0025)$

Thus, we are 98% confidence that the true mean of the scale readings is between 10.0021 and 10.0025.

Part B:

To get a margin of error of +/- 0.0001 with a 98% confidence, then

$\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right)=\pm0.0001 \\ \\ \Rightarrow2.33\left(\frac{0.0002}{\sqrt{n}}\right)=0.0001 \\ \\ \Rightarrow\left(\frac{0.0002}{\sqrt{n}}\right)= \frac{0.0001}{2.33} =0.0000429 \\ \\ \Rightarrow\sqrt{n}= \frac{0.0002}{0.0000429} =4.66 \\ \\ \Rightarrow n=4.66^2=21.7156\approx22$

Therefore, the number of <span>measurements that must be averaged to get a margin of error of ±0.0001 with 98% confidence is 22.</span>

8 0

3 years ago

GUYS HELP PLEASE URGENT!!!!!!

kkurt [141]

Well that would equate to 3136. So I would guess grams.

8 0

3 years ago

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